The someSort function shown in an earlier question runs faster if the input array is already sorted. O True False
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![Analyze the otherSort sorting function. What is its time-
complexity in terms of the size of the input array it sorts if
the array is in random, unsorted order?
T *otherSort(T *arr, int N) {
for (int idxUnsorted = 1; idxUnsorted < N; idxUns
orted++) {
arr[idxUnsorted];
int idxCursor = idxUnsorted;
while ((idxCursor > 0) && (arr[idxCursor
T cur =
1]
> cur)) {
arr[idxCursor
1];
arr[idxCursor]
idxCursor--;
arr[idxCursor]
= cur;
return arr;
O (log n)
0 0 (n²)
O (n!)
O (n)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F971e70ab-a7f7-435c-aa97-68c656c1d94e%2F066b8f61-852f-45fd-a9aa-88a4850e3e2d%2Ff8ikhkg_processed.jpeg&w=3840&q=75)
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- Java Insertion Sort but make it read the data 12, 11, 13, 5, 6 from a file not an array // Java program for implementation of Insertion Sort public class InsertionSort { /*Function to sort array using insertion sort*/ void sort(int arr[]) { int n = arr.length; for (int i = 1; i < n; ++i) { int key = arr[i]; int j = i - 1; /* Move elements of arr[0..i-1], that are greater than key, to one position ahead of their current position */ while (j >= 0 && arr[j] > key) { arr[j + 1] = arr[j]; j = j - 1; } arr[j + 1] = key; } } /* A utility function to print array of size n*/ static void printArray(int arr[]) { int n = arr.length; for (int i = 0; i < n; ++i) System.out.print(arr[i] + " "); System.out.println(); } // Driver method…Java Selection Sort but make it read the data 64, 25, 12, 22, 11 from a file not an array // Java program for implementation of Selection Sort class SelectionSort { void sort(int arr[]) { int n = arr.length; // One by one move boundary of unsorted subarray for (int i = 0; i < n-1; i++) { // Find the minimum element in unsorted array int min_idx = i; for (int j = i+1; j < n; j++) if (arr[j] < arr[min_idx]) min_idx = j; // Swap the found minimum element with the first // element int temp = arr[min_idx]; arr[min_idx] = arr[i]; arr[i] = temp; } } // Prints the array void printArray(int arr[]) { int n = arr.length; for (int i=0; i<n; ++i) System.out.print(arr[i]+" "); System.out.println(); } // Driver code to test above public…9.). integer array nums and an integer k, return the length of the shortest non-empty subarray of nums with a sum of at least k. If there is no such subarray, return -1. A subarray is a contiguous part of an array. Example 1: Input: nums = [1], k = 1 Output: 1 Example 2: Input: nums = [1,2], k = 4 Output: -1 Example 3: Input: nums = [2,-1,2], k = 3 Output: 3.
- array unordered Arr has unsorted integers. SortedArr is an integer array. SortedArr performs which task better than unsortedArr? Use the fastest algorithms. Inserting a new element II Searching for a given element III Calculating the mean of the elements (A) I alone (B) II alone (C) III alone (D) I and II alone (E) I, II, and IIIimplement QuickSort of ints that sorts the numbers in the non-decreasing order. Implement the rearrange function using QuickSort ( such that the pivot is set on the extreme left and the rearrangement is carried on on two pointers) using the O(n) time algorithmThe function gets as input an array, and index of the pivot.The function rearranges the array, and returns the index of the pivot after the rearrangement. int rearrange(int* A, int n, int pivot_index); Implement the QuickSort algorithm. - For n<=2 the algorithm just sorts the (small) array (smaller number first). - For n>=3 the algorithm uses the rearrange function with the pivot chosen to be the median of A[0], A[n/2], A[n-1]. void quick_sort(int* A, int n);In a non-empty array of integers, the priority of a number is determined by thefrequency of its occurrence. Elements are added as they come but the most frequentelement is deleted first. If two elements have the same priority, then the elementwhich came first will be deleted first. For example: nums = [1,2,3,1,3,1,3,2,3]. Afterthe first deletion now the array will be num={1,2,1,1,2}. Implement a priority queuefor the aforementioned scenario.
- Let A = [n, n − 1, n − 2, . . . , 3, 2, 1] be an array where the first n positive integers are listed in decreasing order. Determine whether Heapsort or Quicksort sorts this array faster.For this question, assume the Quicksort pivot is always the right-most element.Write a program that reads an array A of N elements containing only 0's and 1's. Your program should find the position of a 0 and replace it with a 1 to get the longest continuous sequence of 1's. Let this position of 0 be called P. Print P if such a 0 exists and print -1 if the original array A contains only 1's. Assume the array indexing starts from 0.Code only_Given an unsorted array A of size N that contains only positive integers, find a continuous sub-array that adds to a given number S and return the left and right index(1-based indexing) of that subarray. In case of multiple subarrays, return the subarray indexes which come first on moving from left to right. Note:- You have to return an ArrayList consisting of two elements left and right. In case no such subarray exists return an array consisting of element -1..
- Implement the following algorithms in Java: A) A variant of QUICKSORT which returns without sorting subarrays with fewer than k elements and then uses INSERTION-SORT to sort the entire nearly-sorted array (slide 24).B) A variant of QUICKSORT using the median-of-three partitioning scheme.Slide 24:•Cutoff to INSERTION-SORT (as in MERGE-SORT). Alternatively: −When calling QUICKSORT on a subarray with fewer than k elements, return without sorting the subarray −After the top-level call to QUICKSORT returns, run INSERTION-SORT on the entire array to finish the sorting process −Taking advantage of the fast running time of INSERTION-SORT when its input is “nearly” sorted •Tail call optimisation convert the code so that it makes only one recursive call −Usually good compilers do that for us • Iterative version with the help of an auxiliary stackWhat is time complexity for this Bubble Sort algorithm in seconds/minutes? def bubbleSort(array): length = len(array) for i in range(length-1): for j in range(0, length-i-1): if array[j] > array[j+1] : array[j], array[j+1] = array[j+1], array[j] arr = [56,7,1,9,0,4,34,100,67] print ("Elements of array before sorting:") for i in range(len(arr)): print ("%d" %arr[i]), bubbleSort(arr) print ("Elements of array after sorting:") for i in range(len(arr)): print ("%d" %arr[i])Write an algorithmic faster version of this code. So the version that copies values from the first sorted half to a temp array then merges the values from the temp arr and the second sorted half into the original arr. public static <T extends Comparable<T>> void MergeSorting(T[] arr) {T[] tep = (T[]) new Comparable[arr.length];MergeSorting(arr, tep, 0, arr.length - 1);}//Recursive helper method for the merge sort algorithm.//arr The array to sort//tep Temporary array for merge operation//start Index of the left end of the region to sort //end Index of the right end of the region to sort. private static <T extends Comparable<T>> void mergeSort(T[] arr, T[] tep, int start,int end) {if (start >= end) {return;}int middle = (left + right) / 2;MergeSorting(arr, tep, start, middle); // first halfMergeSorting(arr, tep, middle + 1, end); //second halfMerge(arr, tep, start, middle, end);}private static <T extends Comparable<T>> void Merge(T[] arr, T[] tep,…
