The spherical body shown in the figure has a mass of 0.5-kg and is horizontal of OA rod in a frictionless groove it is forced to move with its rotation. Rod e (tetha dot) = 3 rad / s rotates with a fixed angular. As soon as 0 = 30°: a. The force the rod exerts on the sphere and, b. Find the normal reaction force of the channel. Note: Please note that the sphere is in contact with only one side of the channel. You can treat the sphere as a material point.

International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter7: Dry Friction
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Problem 7.81P: Calculate the horizontal force P required to push the 85-lb lawn mower at constant speed. The center...
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The spherical body shown in the figure has a mass of 0.5-kg and is horizontal
of OA rod in a frictionless groove it is forced to move with its rotation.
Rod 8 (tetha dot) = 3 rad / s rotates with a fixed angular. As soon as 0 = 30°:
a. The force the rod exerts on the sphere and,
b. Find the normal reaction force of the channel.
Note: Please note that the sphere is in contact with only one side of the
channel. You can treat the sphere as a material point.
Transcribed Image Text:The spherical body shown in the figure has a mass of 0.5-kg and is horizontal of OA rod in a frictionless groove it is forced to move with its rotation. Rod 8 (tetha dot) = 3 rad / s rotates with a fixed angular. As soon as 0 = 30°: a. The force the rod exerts on the sphere and, b. Find the normal reaction force of the channel. Note: Please note that the sphere is in contact with only one side of the channel. You can treat the sphere as a material point.
0.8 m
Transcribed Image Text:0.8 m
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