The standard reaction free energy AG=-1181. kJ for this reaction: 4 H,0,) + PbS(s)– PBSO(s) + 4 H,0(1) Use this information to complete the table below. Round each of your answers to the nearest kJ. reaction AG x10 8H,0,() + 2PBS(s) 2PBSO,(s) + 8H,0(1) PbSo,6) + 4H,0 () 4H,0,(1) + PbS(s) Poso,(6) + 2H,0 (1) → 2H,0,(1) + ; PbS(s)

Chemistry for Engineering Students
4th Edition
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Author:Lawrence S. Brown, Tom Holme
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Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.77PAE
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The standard reaction free energy AG=-1181. kJ for this reaction:
4 H,O2) + PbS(s)→ PBSO (s) + 4H,O(1)
Use this information to complete the table below. Round each of your answers to the nearest kJ.
reaction
AG
8H,0, () + 2PBS(s) -
2 PbSo,(s) + 8H,0(1)
kJ
PbSO,(6) + 4H,0 (1) - 4H,0,(1) + PbS(s)
1
POSO,() + 2H,0(1) → 2H,0,(1) + ; PbS(s)
Transcribed Image Text:The standard reaction free energy AG=-1181. kJ for this reaction: 4 H,O2) + PbS(s)→ PBSO (s) + 4H,O(1) Use this information to complete the table below. Round each of your answers to the nearest kJ. reaction AG 8H,0, () + 2PBS(s) - 2 PbSo,(s) + 8H,0(1) kJ PbSO,(6) + 4H,0 (1) - 4H,0,(1) + PbS(s) 1 POSO,() + 2H,0(1) → 2H,0,(1) + ; PbS(s)
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