The surface area of a sphere, initially zero, increases uniformly at the rate of 4 xq.in. per sec Find the rate at which the radius is increasing at the end of 2seconds.

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Q: | Va3+1 dx dy 0,

A: ∫01∫y1x3+1dxdy=∫01∫0x2x3+1dydx=∫01x3+1x2-0dx=∫01x2x3+1dx

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A: Step by step Answer is mentioned below

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Q: a

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A: The solution of the problem is given in the next step.

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