The switch has been closed for a very long time before opening at t=0s.t=0t=02.7 kQVc5 μF50 kQ120 V10 kQa.) Capacitor voltage (in Volts) right before the switch has been openedb.) Time constant of the circuit for t > 0. Express your answer in ms.c.) Expression for the capacitor voltage for t > 0d.) Expression for the capacitor current for t > 0e.) Sketch Ic(t) and Vc(t) for t > 0f.) Total dissipated energy (in microjoules) in the 10k ohm resistor 5ms after the switch has beenopened

Answered: Image /qna-images/answer/75a88b2a-088a-462b-9d0b-3dde00a8c283.jpg

Answered: The switch has been closed for a very…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Consider the given circuit. The switch has been closed for a very long time before opening at t=0s. Determine the capacitor voltage (in volts) right before the switch has been opened, the time constant of the circuit for t>0 (in ms), and the expression for the capacitor voltage for t≥0.
In Figure, suppose the switch has been closed for a time interval sufficiently long (steady state) for the capacitor to become fully charged. R 1 = 9 kΩ, R 2 = 12 kΩ, R 3 = 2 kΩ, C = 14 × 10 −6 F, and an ideal battery has emf ε = 12 V. The switch is now opened at t = 0. Find the current in R 2 at time t = 0.09 s. (Your result must be in mA's and include 3 digit after the decimal point. Maximum of 5% of error is accepted in your answer.)
In the circuit shown below, the switch has been open a long time and the circuit is initially in steady-state. At t=0, the switch is closed. R1=0.2Ω, and R2=0.4Ω. The batteries have EMFs E1=1V and E2=3V. The capacitor has capacitance 10 μF. Hint: What is the voltage on the capacitor just before the switch is closed? Note that there is a voltage drop over the open switch. a) What is the voltage over the capacitor before the switch is closed? b) Draw the Thevenin equivalent circuit as seen by the capacitor. c) What is the time constant for charging the capacitor? d) What is the voltage on the capacitor as a function of time?
The voltage pulse applied to the 100 mH inductor shown is 0 for t<0 and is given by the expressionv(t)=20te−10t V for t>0. Also assume i=0 for t≤0.. Find the inductor current as a function of time.
Let Vs=530tᶾ v, leg t >0 and iL (0) = 1 A, in the circuit shown, at t=0.2s, determine the values of the energy stored in the capacitor and the coil. The circuit is in the attached image.
When a capacitor holding an initial electrical charge of 60 microcoulombs (µC) is discharged through an electrical circuit, the remaining charge on the capacitor is q(t) = 60e-t/4 , where t is time elapsed in seconds. (a) Find q'(t), the electrical current in the circuit, as a function of t. (b) When is the magnitude of the electrical current in the circuit the greatest, and what is its value at this time?
From the given circuit. Switch S1 is in position A switch S2 is open. Both switches are in these states for a very long time. At t=0, switch S1 moves from position A to B while switch S2 remains open. 10ms after switch S1 moves to position B, switch S2 is closed and remains closed for 20ms only. ANSWER THE FOLLOWING: a.) Expression for the inductor current for 0 ≤ ? < 10??b.) Expression for the inductor current for 10?? ≤ ? < 30?? and 30?? ≤ ? < ∞c.) What is the time (in ms) after switch S1 moves to position B is the current in the inductor equivalent to 30% of the initial value (at ?=0).
A capacitor consists of two circular plates of radius a separated by a distance d(assume d << a). The centre of each plate is connected to the terminals of a voltagesource by a thin wire. A switch in the circuit is closed at time t = 0 and a current I(t) flows in the circuit. Thecharge on the plate is related to the current according to I (t) = dq/dt. We begin bycalculating the electric field between the plates. Throughout this problem you mayignore edge effects. We assume that the electric field is zero for r > a.(A) Use Gauss’ Law to find the electric field between the plates as a functionof time t, in terms of q(t), a, ε, and π. The vertical direction is the k direction. (B)Now take an imaginary flat disc of radius r < a inside the capacitor, as shownbelow. Using your expression for E above, calculate the electric flux through this flatdisc of radius r < a in the plane midway between the plates, in terms of r, q(t), a,and ε. (C)Calculate the Maxwell displacement…
All capacitors were initially discharged. at t = 0, S1 is placed at position 1 and S2 is closed. During this phase, it has been determined that Eth and Rth seen by the equivalent capacitor are, respectively, 20 V and 6.0 kΩ. The time constant is 29 ms. At t = 15 ms, S1 is placed at position 2 and S2 is kept closed. Calculate the equivalent capacitor voltage vT at t = 15 ms. Enter your answer in V rounded to 2 decimal places. At t = 25 ms, S1 is kept at position 2 and S2 is opened. Data: R1 = 5 kΩ, R2 = 3 kΩ, R4 = 2 kΩ, R5 = 20 kΩ, R6 = 12.0 kΩ;
a. Find the mathematical expressions for the transient behavior of thevoltage vC and the current iC if the capacitor was initially unchargedand the switch is thrown into position 1 at t = 0 s.b. Find the mathematical expressions for the voltage vC and the current iCif the switch is moved to position 2 at t = 3 ms.c. Find the mathematical expressions for the voltage vC and the current if theswitch is thrown into position 3 at t =5 ms.d. Plot the waveforms obtained in parts (a)–(c)
The switch in the circuit has been in position a fora long time. At t=0, the switch moves instantaneously to position band stays there. Find the initial and final values of the capacitorvoltage, the time constant for t≥0, and the expression for thecapacitor voltage for t≥0.
An inductance of 1 H, a resistance of 8 Ω and capacitance of 0.04 F are connected in series with a variable voltage E = 50 sin 3t. Find the current and charge in the system, given the initial conditions q = 0 and l = 0 when t = 0, using method of solution of higher order linear ordinary differential equation.

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