The total of electrons lost that is equal to the total number of electrons gained in the balanced equation below is * 3MNO4¯ + 24H* + 5Fe → 3Mn²+ + 5FE3+ + 12H2O 5 e З е- 15e- бе-
The total of electrons lost that is equal to the total number of electrons gained in the balanced equation below is * 3MNO4¯ + 24H* + 5Fe → 3Mn²+ + 5FE3+ + 12H2O 5 e З е- 15e- бе-
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter21: Nuclear Chemistry
Section: Chapter Questions
Problem 43E: A B58 atom (mass = 8.0246 amu) decays into B48 atom (mass = 8.0053 amu) by loss of a + panrticle...
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