The two charges in Figure are separated by d=2 cm. 92 60.0° В -15.0 nC 27.0 nC

Physics for Scientists and Engineers: Foundations and Connections
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ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter24: Electric Fields
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Problem 6PQ: Is it possible for a conducting sphere of radius 0.10 m to hold a charge of 4.0 C in air? The...
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find the electric field exerted by the negative charge at point B, as well as the electric field exerted by the positive charge at point B

The two charges in Figure are separated by d=2 cm.
60.0°
+.
-15.0 nC
27.0 nC
Transcribed Image Text:The two charges in Figure are separated by d=2 cm. 60.0° +. -15.0 nC 27.0 nC
Expert Solution
Step 1

Given data:

Charges are given as,

q1 = 27 nC

q2 = -15 nC

Distance between charges is,

d= 2 cm 

Formula used:

Electric field intensity is given as,

E = 14πε0qr2r^

Where,

r- Distance between source charge and the test charge

q- Source charge

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