The unbalance equation for the reaction between bromine, Br2(aq), and iodate ion, IO3-(aq), in acidic solution is Br2(aq) + IO3-(aq) à Br -(aq) + IO4-(aq). What volume of 0.788 mol/L of KIO3(aq) will react with 4.00 g of Br2(aq)?
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The unbalance equation for the reaction between bromine, Br2(aq), and iodate ion, IO3-(aq), in acidic solution is Br2(aq) + IO3-(aq) à Br -(aq) + IO4-(aq). What volume of 0.788 mol/L of KIO3(aq) will react with 4.00 g of Br2(aq)?
Hint: use n = CV
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- An analyst is planning to standardize a 0.200 mol/L NaOH solution for use in neutralization. For this, he chose to standardize the NaOH solution using potassium hydrogen phthalate. (KHC8O4H4, molecular mass 204.22 g mol/L) - Knowing that potassium hydrogen phthalate is a solid, what is the mass of potassium hydrogen phthalate in grams, the analyst should weigh to standardize the NaOH, anticipating spending 15 mL of NaOH solution approximately 0.200 mol/L ? [Answer; m=0.6123 g] NaOH + KHC8O4H4 → KNaC8O4H4 + H2O(Neutralization reaction in standardization) - Why you need to standardize the NaOH solution and why use potassium hydrogen phthalate?Tartaric acid, H2C4H4O6, is a diprotic acid that naturally occurs in the production of wine. Jose was tasked to find out the acid content in a 100.0 mL wine sample by titrating it with a standardized solution of NaOH. He was able to establish the working concentration of the NaOH solution by using 35.21 mL of it to titrate a primary standard of KHP that weighed 3.001 g. The grams and %w/w of Tartaric acid present in the 100.0 mL wine sample were then determined by titrating a 25.00 mL aliquot using 43.56 mL of the standardized NaOH solution. H2C4H4O6 (aq) + 2NaOH (aq) ↔ Na2C4H4O6 (aq) + 2H2O (l) Assume that the density of the wine sample is 1.000 g/mL MM of KHP = 204.22 g/mol MM of H2C4H4O6 = 150.087 g/mol What is the molar concentration of the prepared NaOH solution?…Tartaric acid, H2C4H4O6, is a diprotic acid that naturally occurs in the production of apple wine. Emma was tasked to find out the acid content in a 50.0 mL wine sample by titrating it with a standardized solution of NaOH. She was able to establish the working concentration of the NaOH solution by using 17.61 mL of NaOH to titrate a primary standard of KHP that weighed 1.501 g. The grams and %w/w of Tartaric acid present in the 50.0 mL wine sample were then determined by titrating a 12.50 mL aliquot using 21.78 mL of the standardized NaOH solution. H2C4H4O6 (aq) + 2NaOH (aq) ↔ Na2C4H4O6 (aq) + 2H2O (l) Assume that the density of the wine sample is 1.000 g/mL MM of KHP = 204.22 g/mol MM of H2C4H4O6 = 150.087 g/mol What is the molar concentration of the prepared NaOH solution?…
- 3. The concentration of acetylsalicylic acid, C9H8O4, in aspirin tablets is determined by hydrolyzing it to the salicylate ion, C7H5O3-, and de¬termining its concentration spectrofluorometrically. A stock standard solution is prepared by weighing 0.0774 g of salicylic acid, C7H6O3, into a 1-L volumetric flask and diluting to volume. A set of calibration standards is prepared by pipeting 0, 2.00, 4.00, 6.00, 8.00, and 10.00 mL of the stock solution into separate 100-mL volumetric flasks that contain 2.00 mL of 4 M NaOH and diluting to volume. Fluorescence is measured at an emission wavelength of 400 nm using an excitation wavelength of 310 nm with results shown in the following table. (a) Why is the excitation wavelength (310 nm) shorter than the emission wavelength (400 nm)?(b) How is the emission wavelength isolated from the excitation wavelength in a fluorescence instrument?A student prepares a dilute solution of sodium hydroxide, NaOH (aq), starting with 6 M sodium hydroxide. She then titrates a 1.372 g sample of KHP with the dilute sodium hydroxide solution, NaOH (aq), to a phenolphthalein end point. a) If the titration required 21.84 mL of sodium hydroxide, NaOH (aq), calculate the molar concentration of the sodium hydroxide solution, NaOH (aq). (Remember that KHP is potassium hydrogen phthalate, KHC8H4O4, NOT potassium hydrogen phosphorus!) b) The student uses the same sodium hydroxide to titrate 10.00 mL of vinegar to a phenolphthalein end point. If the titration required 27.48 mL of sodium hydroxide, NaOH (aq), calculate the molar concentration of acetic acid, HC2H3O2 (aq), in the vinegar. c) Calculate the mass percent of acetic acid, HC2H3O2(aq), in the vinegar using the molar concentration for acetic acid, HC2H3O2 (aq), determined in part b and assuming the density of the solution is 1.01 g/mL.A student prepares a dilute solution of sodium hydroxide, NaOH (aq), starting with 6 M sodium hydroxide. She then titrates a 1.372 g sample of KHP with the dilute sodium hydroxide solution, NaOH (aq), to a phenolphthalein end point. A.) If the titration required 21.84 mL of sodium hydroxide, NaOH (aq), calculate the molar concentration of the sodium hydroxide solution, NaOH (aq). (Remember that KHP is potassium hydrogen phthalate, KHC8H4O4, NOT potassium hydrogen phosphorus!) B.) The student uses the same sodium hydroxide to titrate 10.00 mL of vinegar to a phenolphthalein end point. If the titration required 27.48 mL of sodium hydroxide, NaOH (aq), calculate the molar concentration of acetic acid, HC2H3O2 (aq), in the vinegar. C.) Calculate the mass percent of acetic acid, HC2H3O2 (aq), in the vinegar using the molar concentration for acetic acid, HC2H3O2 (aq), determined in part b and assuming the density of the solution is 1.01 g/mL.
- Complete the followin reaction by providing the products formed. Then balance the reaction and write the molecular reaction and the total and net ionic reactions. The reaction is: Zn(NO3)2 (aq) + Ba(OH)2 (aq) ---> Products.The ubbalance equation for the reaction between bromine, Br2, and aqueous iodate ion IO3^- in acidic solution. What volume in mL of .877M KlO3 will react with 6.00g Br2. Br2(aq)+IO3- = Br- +IO4^-A 1.4350-gram of KHP (actual formula = KHC8H4O4; molar mass = 204.22 g/mol) was dissolved in 50.00 mL of deionized water. The resulting solution was titrated with NaOH solution of unknown concentration. If 32.85 mL of the NaOH solution was required to reach the equivalent point, what was the molar concentration of the NaOH solution? The acid-base reaction is as follows: KHC8H4O4(aq) + NaOH(aq) --> NaKC8H4O4(aq) + H2O(l) (A) 0.1405 M (B) 0.2139 M (C) 0.08481 M (D) 7.0267 x 10–3 M
- The mass of a solid piece of iron Fe(s) should be determined by allowing it to react with a solution of 0.500 L potassium dichromate K2Cr2O7 (aq) in a redox reaction in acidic solution, so that all iron is oxidized into iron (II) ions, Fe2+(aq). Concomitant chromium(III) ions, Cr3+(aq), after the reduction equation: Cr2O7 2−(aq) + 14H +(aq) + 6e − → 2Cr3+(aq) + 7H2O(l) a) Write the complete and balanced reaction equation for the redox reaction where the piece of iron is oxidized into iron (II) ions by the dithromations in the solution. b) A sample of the reaction solution after the oxidation of iron is completed shows that the molar concentration of Cr3+ ions is 0.0162 M. What is the calculated mass of the piece of iron Fe(s) in grams? c) What is the amount of electrons e − in moles transmitted in this specific reaction? Calculate the electrical work wel the oxidation of the piece of iron has created in kilojoules (kJ), using the enclosed electrode potentials E 0 and the…Aqueous sodium hypochlorite (NaOCl, household bleach) is a strong oxidizing agent that reacts with chromite ion [Cr(OH)4-] in basic aqueous solution to yield chromate ion CrO42- and chloride ion Cl-. The next ionic equation is: ClO- (aq) + Cr(OH)4-(aq) ------> CrO42-(aq) + Cl-(aq) Unbalanced Balance the equation using the method described in section 1 of the Electrochemistry chapter.Aspirin, acetylsalicylic acid, C9H8O4, reacts with basic substances. If the titration of an aspirin tablet (with mass equal to 1,000 g) requires 25.43 mL of 0.100 M NaOH to reach the end point. How many grams of acetylsalicylic acid are in the tablet? What is the percent by mass of acetylsalicylic acid in the tablet?