Q5/A: The boom OAB pivotsabout point O, while section ABextends fromsimultaneouslywithin section OA. Determinethe velocity and acceleration ofcenter B of the pulley for thefollowing conditions: 0 = 20degree, 0^. = 5 deg/sec, 0^(..)=2 deg/sec^2, L= 7 m, L^= 1.5m/s, L^() = -4 ms^2.B241AO

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Answered: the velocity and acceleration of center…

Engineering

Civil Engineering

the velocity and acceleration of center B of the pulley for the

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Equilibrium and Support Reactions

Civil engineers deal with structures that are composed of several members connected or with individual members such as beams and columns. To analyze such structures, the condition of statics must be applied. Under the static condition, the members are considered to be in equilibrium under the action of forces, that is, the members are assumed to be having negligible velocity.

Question

Q5/A: The boom OAB pivots
about point O, while section AB
extends from
simultaneously
within section OA. Determine
the velocity and acceleration of
center B of the pulley for the
following conditions: 0 = 20
degree, 0^. = 5 deg/sec, 0^(..)=
2 deg/sec^2, L= 7 m, L^= 1.5
m/s, L^() = -4 ms^2.
B
24
1
A
O

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sorry，what are these： Step 3 Slope deflection equation In section AB MAB= MFAB+22EIL2θA+θB-3δLMAB= -12.5+4EI5θB MBA= 12.5+4EI52θB In section BC MBC= 0+2EI52θB+θC MCB= 2EI5θB+2θC In section CD MCD= -16.67+4EI52θC MDC= 16.67+4EI5θC arrow_forward Step 4 Equilibrium equations Equilibrium equations MBA+MBC= 0 -(i)MCB+MCD= 0 -(ii) Now, From i12.5+8EIθB5+4EIθB5+2EIθC5= 0EIθB125+EIθC25 = -12.5 -(iii) From ii2EIθB5+4EIθC5+-16.67+8EIθC5=02EIθB5+EIθC125= 16.67 iv Solving equations (iii) and (iv), we get EIθB= -6.548EIθC = 8.037