The velocity as a function of time is given as v(t) = 6t−t2 in m/s and t in seconds (s). Consider the time interval from t=0 tot = 12A:Find the time after t=0 when the particle changes direction.B:Find the time before which the acceleration is positive.C:What is the displacement of the object in the time interval given above?

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Asked Nov 22, 2019
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The velocity as a function of time is given as v(t) = 6t−t2 in m/s and t in seconds (s). Consider the time interval from t=0 tot = 12

A:Find the time after t=0 when the particle changes direction.

B:Find the time before which the acceleration is positive.

C:What is the displacement of the object in the time interval given above?

 

 

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Expert Answer

Step 1

Given:

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(t)= 6f-t

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Step 2

Part (a): at time after t=0 when the particle changes direction, its velocity at that time become zero

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6t -t0 6-t 0 t =6sec

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Step 3

Part (b): time before which the acceleration is positive implies that ac...

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a 0 dv =0 dt put the value ofv d(6r-) =0 dt d(6t) d(t) dt dt 6 2 0 6 2t t 3sec

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