The velocity of an object moving along a line is given by v = 2t2 + 5 ft/s on the interval 0sts4. a. Divide the interval [0, 4] into subintervals, [0, 1], [1, 2], [2, 3], and [3, 4]. On each subinterval, assume the object moves at a constant velocity equal to the value of v evaluated at the midpoint of the subinterval and use these approximations to estimate the displacement of the object on [0, 4]. (See part (a) of the figure.) b. Repeat part (a) for n= 8 subintervals (see part (b) of the figure). W Click the icon to view the figures. - X Figures for (a) and (b) 40- 40어 20- 20- (a) (b)

The velocity of an object moving along a line is given by v = 2t2 + 5 ft/s on the interval 0sts4. a. Divide the interval [0, 4] into subintervals, [0, 1], [1, 2], [2, 3], and [3, 4]. On each subinterval, assume the object moves at a constant velocity equal to the value of v evaluated at the midpoint of the subinterval and use these approximations to estimate the displacement of the object on [0, 4]. (See part (a) of the figure.) b. Repeat part (a) for n= 8 subintervals (see part (b) of the figure). W Click the icon to view the figures. - X Figures for (a) and (b) 40- 40어 20- 20- (a) (b)

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter3: Motion In Two Dimensions

Section: Chapter Questions

Problem 42P: A landscape architect is planning an artificial waterfall in a city park. Water flowing at 1.70 m/s...

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