The Vertex and the value of 'p' of the given parabola (x – 5)² = 16(y – 6) are O Vertex = (-5, –6); p= –4 O Vertex = (5, 6); p= -4 O Vertex = (-5, –6) ; p= 4 O Vertex = (5, 6) ; p = 4

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.6: Quadratic Functions
Problem 32E
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The Vertex and the value of 'p' of the given parabola (x – 5)² = 16(y – 6) are
O Vertex = (-5, –6); p= –4
O Vertex = (5, 6) ;
p = -4
O Vertex = (-5, –6) ; p= 4
O Vertex = (5, 6) ;
p = 4
Transcribed Image Text:The Vertex and the value of 'p' of the given parabola (x – 5)² = 16(y – 6) are O Vertex = (-5, –6); p= –4 O Vertex = (5, 6) ; p = -4 O Vertex = (-5, –6) ; p= 4 O Vertex = (5, 6) ; p = 4
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