The vertex of a parabola is (6,2), and the equation of its directrix is y = 0. What is the equation of this parabola in standard form? O (y- 2) = -8(z – 6) o (z- 6) -8 (y– 2) O (z-6) = -8 (y – 2) O (y-2) -8 (z – 6) 6. 7.
The vertex of a parabola is (6,2), and the equation of its directrix is y = 0. What is the equation of this parabola in standard form? O (y- 2) = -8(z – 6) o (z- 6) -8 (y– 2) O (z-6) = -8 (y – 2) O (y-2) -8 (z – 6) 6. 7.
College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter7: Conic Sections
Section7.1: Parabolas
Problem 3E: The graph of the equation y2=4px is a parabola with focus F(__, __) and directrix x = ____. So the...
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