The voltage pulse shown inis applied to the idealintegrating amplifier shownin and v. (0) = 0.Vg (mv)2000-200425025 knww1=05005 MOw400 nFHE6V-6V1 (ms) Part ADerive the numerical expression for u.(t) for the time interval t < 0.Express your answer in terms of t, where t is in seconds.vo(t)=Part BVDerive the numerical expression for u(t) for the time interval 0 ≤t≤ 250 ms.Ovo(t)=200(1-e 100) VOvo(t)=40(1e-100) VOvo(t) 200(1-e-05) VOvo(t)=40(1-e 0.5t) V

Given:Input, to the circuit, To derive:a) b)

Answered: The voltage pulse shown in is applied…

The voltage pulse shown in is applied to the ideal integrating amplifier shown in and v. (0) = 0. Vg (mv) 200 0 -200 250 25 kn 500 5 MO w 400 nF HE 6 V -6V 1 (ms)

Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter18: Resistive-inductive Parallel Circuits

Section: Chapter Questions

Problem 13PP: In an R-L parallel circuit, IT=1.25 amps, R=1.2k, and XL=1k. Find IR

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Concept explainers

Operational Amplifier

An operational amplifier also called op amp is an integrated circuit or analog circuit that takes input as a differential voltage and produces output as a single-ended voltage. It is an IC that can amplify weak electric signals.An op amp has one output pin and two input pins. The basic role of an opamp is to amplify the voltage difference between the two input voltages. It is also used in filtering or to perform mathematical operations or in signal conditioning.

Question

The voltage pulse shown in
is applied to the ideal
integrating amplifier shown
in and v. (0) = 0.
Vg (mv)
200
0
-200
4
250
25 kn
ww
1=0
500
5 MO
w
400 nF
HE
6V
-6V
1 (ms)

Part A
Derive the numerical expression for u.(t) for the time interval t < 0.
Express your answer in terms of t, where t is in seconds.
vo(t)
=
Part B
V
Derive the numerical expression for u(t) for the time interval 0 ≤t≤ 250 ms.
Ovo(t)=200(1-e 100) V
Ovo(t)=40(1e-100) V
Ovo(t) 200(1-e-05) V
Ovo(t)=40(1-e 0.5t) V

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