The voltage, V, (in volts) across a circuit is given by Ohm's law: V = IR, where I is the current (in amps) flowing through the circuit and Ris the resistance (in ohms). If we place two circuits, with resistance R1 and R2, in parallel, then their combined resistance, R, is 1 given by- 1 1 +- Suppose the current is 5 amps and increasing at 10- amp/sec and R is 6 ohms and increasing at 0.3 R1 R2 %3D ohm/sec, while R2 is 3 ohms and decreasing at 0.4 ohm/sec. Calculate the rate at which the voltage is changing.

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Author:Bruce Crauder, Benny Evans, Alan Noell
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The voltage, V, (in volts) across a circuit is given by Ohm's law: V = IR, where I is the current (in amps) flowing through the circuit
and Ris the resistance (in ohms). If we place two circuits, with resistance R and R2, in parallel, then their combined resistance, R, is
1
given by
R
1
1
Suppose the current is 5 amps and increasing at 10-2 amp/sec and R is 6 ohms and increasing at 0.3
R2
R1
ohm/sec, while R2 is 3 ohms and decreasing at 0.4 ohm/sec. Calculate the rate at which the voltage is changing.
The absolute tolerance is + 0.001. three decimal places.
volts/sec
eTextbook and Media
Hint
Assistance Used
Theorem (Two-Variable Chain Rule)
If x = x(t) and y = y(t) are differentiable at t, and if z = f(x, y) is differentiable at the point (x, y) = (x(t), y(t)), then
z = f(x(t), y(t)) is differentiable at t and
dz
dzdx
dzdy
%3D
dt
dx dt
dy dt
where the ordinary derivatives are evaluated at t and the partial derivatives are evaluated at (x, y).
Transcribed Image Text:The voltage, V, (in volts) across a circuit is given by Ohm's law: V = IR, where I is the current (in amps) flowing through the circuit and Ris the resistance (in ohms). If we place two circuits, with resistance R and R2, in parallel, then their combined resistance, R, is 1 given by R 1 1 Suppose the current is 5 amps and increasing at 10-2 amp/sec and R is 6 ohms and increasing at 0.3 R2 R1 ohm/sec, while R2 is 3 ohms and decreasing at 0.4 ohm/sec. Calculate the rate at which the voltage is changing. The absolute tolerance is + 0.001. three decimal places. volts/sec eTextbook and Media Hint Assistance Used Theorem (Two-Variable Chain Rule) If x = x(t) and y = y(t) are differentiable at t, and if z = f(x, y) is differentiable at the point (x, y) = (x(t), y(t)), then z = f(x(t), y(t)) is differentiable at t and dz dzdx dzdy %3D dt dx dt dy dt where the ordinary derivatives are evaluated at t and the partial derivatives are evaluated at (x, y).
The voltage, V, (in volts) across a circuit is given by Ohm's law: V = IR, where I is the current (in amps) flowing through the circuit
and Ris the resistance (in ohms). If we place two circuits, with resistance Rj and R2, in parallel, then their combined resistance, R, is
1.
1
given by
Suppose the current is 5 amps and increasing at 10 amp/sec and R is 6 ohms and increasing at 0.3
R2
R1
ohm/sec, while R2 is 3 ohms and decreasing at 0.4 ohm/sec. Calculate the rate at which the voltage is changing.
Round your answer to three decimal places.
volts/sec
eTextbook and Media
Hint
Assistance Used
Theorem (Two-Variable Chain Rule)
If x = x(t) and y = y(t) are differentiable at t, and if z = f(x, y) is differentiable at the point (x, y) = (x(t), y(t)), then
z =f(x(t), y(t)) is differentiable at t and
dz
dzdx
dzdy
dt
dx dt
dy dt
where the ordinary derivatives are evaluated at t and the partial derivatives are evaluated at (x, y).
Transcribed Image Text:The voltage, V, (in volts) across a circuit is given by Ohm's law: V = IR, where I is the current (in amps) flowing through the circuit and Ris the resistance (in ohms). If we place two circuits, with resistance Rj and R2, in parallel, then their combined resistance, R, is 1. 1 given by Suppose the current is 5 amps and increasing at 10 amp/sec and R is 6 ohms and increasing at 0.3 R2 R1 ohm/sec, while R2 is 3 ohms and decreasing at 0.4 ohm/sec. Calculate the rate at which the voltage is changing. Round your answer to three decimal places. volts/sec eTextbook and Media Hint Assistance Used Theorem (Two-Variable Chain Rule) If x = x(t) and y = y(t) are differentiable at t, and if z = f(x, y) is differentiable at the point (x, y) = (x(t), y(t)), then z =f(x(t), y(t)) is differentiable at t and dz dzdx dzdy dt dx dt dy dt where the ordinary derivatives are evaluated at t and the partial derivatives are evaluated at (x, y).
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