The volume of a sphere is decreasing at a constant rate of 5398 cubic meters per second. At the instant when the radius of the sphere is 10 meters, what is the rate of change of the surface area of the sphere? The volume of a sphere can be found with the equation V = Tr and the surface area can be found with S = 4tr². Round your answer to three decimal places (if necessary).
The volume of a sphere is decreasing at a constant rate of 5398 cubic meters per second. At the instant when the radius of the sphere is 10 meters, what is the rate of change of the surface area of the sphere? The volume of a sphere can be found with the equation V = Tr and the surface area can be found with S = 4tr². Round your answer to three decimal places (if necessary).
Mathematics For Machine Technology
8th Edition
ISBN:9781337798310
Author:Peterson, John.
Publisher:Peterson, John.
Chapter26: Customary (english) Units Of Measure
Section: Chapter Questions
Problem 5A: The volume V of a cone with height h and diameter d is given by V=0.2618d2h . What is the volume of...
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The volume of a sphere is decreasing at a constant rate of 5398 cubic meters per second. At the instant when the radius of the sphere is 10 meters, what is the rate of change of the surface area of the sphere? The volume of a sphere can be found with the equation V=4/3πr^3 and the surface area can be found withS=4πr^2. Round your answer to three decimal places (if necessary). ANSWER SHOULD BE IN m^2/sec.
Transcribed Image Text:The volume of a sphere is decreasing at a constant rate of 5398 cubic
meters per second. At the instant when the radius of the sphere is 10
meters, what is the rate of change of the surface area of the sphere?
The volume of a sphere can be found with the equation V = Tr
and the surface area can be found with S = 4rr². Round your answer
to three decimal places (if necessary).
2
m
Answer:
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