The wave function for a standing wave on a string of linear mass density u = 0.2 kg/m, is given by y(x,t) = 0.05 sin(4Tx)cos(60rt), where x and y are in meters and t is in seconds. At what time would %3D an element of the string, located at x = 0.1 m, has its transverse velocity v_y = v_(y.max)/2? V #13 y = 0,5 in (4IT7) (60) t = 1/360 sec %3D 9'= - 0,05xéo sin(lz) ) t = 1/60 sec t = n/60 sec

The wave function for a standing wave on a string of linear mass density u = 0.2 kg/m, is given by y(x,t) = 0.05 sin(4Tx)cos(60rt), where x and y are in meters and t is in seconds. At what time would %3D an element of the string, located at x = 0.1 m, has its transverse velocity v_y = v_(y.max)/2? V #13 y = 0,5 in (4IT7) (60) t = 1/360 sec %3D 9'= - 0,05xéo sin(lz) ) t = 1/60 sec t = n/60 sec

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter16: Wave Motion

Section: Chapter Questions

Problem 16.9P

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