The x-coordinate of a particle in curvilinear motion is given by x = 2.0t3 - 3.0t where x is in feet and t is in seconds. The y- component of acceleration in feet per second squared is given by ay = 4.0t. If the particle has y-components y = 0 and vy= 4.0 ft/sec when t = 0, find the magnitudes of the velocity v and acceleration a when t = 2.0 sec. Sketch the path for the first 2.0 seconds of motion, and show the velocity and acceleration vectors for t = 2.0 sec. Answers: V= i ft/sec

The x-coordinate of a particle in curvilinear motion is given by x = 2.0t3 - 3.0t where x is in feet and t is in seconds. The y- component of acceleration in feet per second squared is given by ay = 4.0t. If the particle has y-components y = 0 and vy= 4.0 ft/sec when t = 0, find the magnitudes of the velocity v and acceleration a when t = 2.0 sec. Sketch the path for the first 2.0 seconds of motion, and show the velocity and acceleration vectors for t = 2.0 sec. Answers: V= i ft/sec

Name: 2 =The x-coordinate of a particle in curvilinear motion is given by x
Uploaded: 2024-03-20T06:57:47.000Z
Channel: Bartleby
Description: 2 =The x-coordinate of a particle in curvilinear motion is given by x = 2.0t3 - 3.0t where x is in feet and t is in seconds. The y-component of acceleration in feet per second squared is given by ay = 4.0t. If the particle has y-components y = 0 and

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

At t=0 an object starts from the origin and moves with a constant acceleration of a→=(−3.2i−2.7j)m/s2 on a horizontal surface. If the initial velocity of the object is vo→=(14.1i−18.3j)m/s, determine the magnitude of velocity at t=2.1s. Express your answer in units of m/sm/s using zero decimal places.
In the two-dimensional motion, what is the magnitude of the y component of the velocity of the projectile when it is at its apex of trajectory? Select one: a. Velocity is equal to the initial velocity b. Velocity is 9.81 m/s c. Velocity is equal to the x component d. Undetermined e. Velocity is 0 m/s
For projectile motion problems, the horizontal and vertical components of the motion of a projectile can be analyzed separately. Which of the following is TRUE about the horizontal component of its motion?a. The horizontal component of the acceleration is constant and is equal to -9.81 m/s^2b. The motion is uniformc. The horizontal component of the velocity varies with positiond. The motion is uniformly accelerated
An object is initially moving in the x-direction at 2.9 m/s when it undergoes acceleration in the y-direction for a period of 14 s. If the object moves equal distances in the x- and y-directions during this time, what’s the magnitude of its acceleration?
In a particular Cartesian coordinate system, the y and z-components of the acceleration are zero and the x-component varies as given by the following function: ax(t) = 5t - 2t2 + 45e-t/F, where t is in seconds, ax is in meters per square second, and the constant F is in seconds. At t = 0, the particle was at position x = 3 m with a velocity pointing towards the positive x-axis and having magnitude 35 m/s. In the following problem you can take the constant F = 1.0 s. Find the instantaneous velocity, in meters per second, at t = 2 s. Find the position, in meters, of the particle at t = 1 s. Find the position, in meters, of the particle at t = 3 s.
An animal has a coordinates of (1.1 m, 3.4 m) at time t1 = 0 and when t2= 3.0 s, it is located at (5.3 m, -0.5 m). For this time interval, find (a) the components of the average velocity, and (b) the magnitude and direction of the average velocity.
A man hits a ball 2.4 m above the ground. If the ball leaves his racket with an initial velocity of 52 m/s in a horizontal direction, what is the magnitude of the range (in meters) that the ball covers? Assume the local acceleration due to gravity to have the magnitude 9.8 m/s2.
At any instant, the horizontal position of the weather balloon is defined by x = 6t ft, where t is in seconds. If the equation of the path is y = x2/10, determine the magnitude of the acceleration in ft/s2 when t = 2 seconds.
An unsuspecting bird is coasting along in an easterly direction at 4.00 mph when a strong wind from the south imparts a constant acceleration of 0.200 m/s2 . If the wind's acceleration lasts for 3.10 s , find the magnitude ?r and direction ?θ (measured counterclockwise from the easterly direction) of the bird's displacement over this time interval. Assume that the bird is originally travelling in the +?+x direction and that there are 1609 m in 1 mi . ?= ? ?= ? Now, assume the same bird is moving along again at 4.00 mph in an easterly direction, but this time, the acceleration given by the wind is at a ϕ=39.0° angle to the original direction of motion, measured counterclockwise from the easterly direction. If the magnitude of the acceleration is 0.500 m/s2 , find the displacement vector ?⃗ r→ and the angle of the displacement ?1θ1 . Enter the components of the vector, ??rx and ??ry , and the angle. Assume the time interval is still 3.10 s . ?⃗ =???̂ +???̂
The x- and y- coordinates of a moving particle are given by the parametric equations below. Find the magnitude and direction of the acceleration for the specific value of t. x=2t, y=3−t, t=2.
A glider is initially moving at a constant height of 3.76 m. It is suddenly subject to a wind such that its velocity at a later time t can be described by the equation v(t) = 16.18 − 7.78(1 + t) + 0.70t3, where v and its components are in meters per second, t is in seconds, and the z axis is perpendicular to the level ground. (a) What was the initial velocity of the glider? (Express your answer in vector form.) vi = m/s(b) Write an expression for the acceleration of the glider in component form when t = 2.14 s. (Express your answer in vector form.) a(t = 2.14 s) = m/s2
The y-coordinate of a particle in curvilinear motion is given by y = 11.3t3 - 11.2t, where y is in inches and t is in seconds. Also, the particle has an acceleration in the x-direction given by ax = 3.1t in./sec2. If the velocity of the particle in the x-direction is 7.5 in./sec when t = 0, calculate the magnitudes of the velocity v and acceleration a of the particle when t = 3.3 sec. Construct v and a in your solution.Answers: When t = 3.3 sec,