The. Nielsen television ratings used a random sample of 2,000 homes and found that 45% of the homes watched a football game on Monday night.  With 95% confidence, what would the margin of error be if this sample was used to estimate the percent of all homes that watch football on Monday night. Round answer to the nearest percent.   a. 3%   b. 5%   c. 2%   d. 1%

Q: 2. Given: n=80, a = 15, level of confidence is 92%. What is the margin of error of the given data?

A:

Q: Given 25 confidence intervals in the figure to the left, which of the following is the most likely…

A: The confidence interval is an inference process which gives the range of plausible values of…

Q: find the margin of error for a sample mean, given n=16, s=4, Xbar=17. for a 95% confidence interval.

A: The margin of error for sample mean is given by,

Q: If n = 590 and ˆp=0.48, find the margin of error at a 99% confidence level E=

A: If n = 590 and ˆp=0.48, find the margin of error at a 99% confidence level

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll,…

A: Given information: x=586 n=1006

Q: Based on a survey of a random sample of 900 adults in the United States, a journalist reportS that…

A:

Q: 4. For the 95% confidence level, A. a.01 B. a .01 C.a=05 D. a = .025 5. Which of the following is…

A: According to the given information in this question  There are lots of questions according to…

Q: In this question If n=20, ¯xx¯(x-bar)=38, and s=8, find the margin of error at a 90% confidence…

A: Given, Sample size = 20 Sample mean = 38 Sample standard deviation = 8   Degrees of Freedom:

Q: A sample consisting of 410 men and 795 women was asked various questions pertaining to international…

A: To find the male sample, female sample and the combined sample :

Q: a recent study of 100 people in Burlingame found that 19 were obese.  Find the 90% confidence…

A:

Q: Political survey- A political analyst found that 43% of 300 randomly seleted republican voters feel…

A: It is given that p hat is 0.43 and sample size is 300. The confidence level is 0.95.

Q: If n = 200 and p^ = 0.64, find the margin of error at a 95% confidence level.

A:

Q: A researcher would like to know the proportion of the households that has a cable subscription. She…

A:

Q: For a two-tailed test, a sample size of 21 at 80% confidence, t= 1.323 2.539 1.325 2.528

A: We have to find correct option..

Q: When asked what they consider to be the best birthday present, 64% of a random sample of  800 adults…

A: The Margin of Eroor (MOE) = z * √p * (1 - p) / √nWhere: z = 1.96 for a confidence level (α) of 95%,…

Q: 例题3: Based on a survey of a random sample of 900 adults in the United States, a journalist reports…

A:

Q: A television sports commentator wants to estimate the proportion of citizens who​ "follow…

A: Solution: a. From the given information, confidence level is 0.96, p=0.48 and E=0.03.

Q: In a​ poll, 51​% of the people polled answered yes to the question​ "Are you in favor of the death…

A: The following information has been provided: p^=0.51E=0.03 The level of significance is : α=1-0.94…

Q: If a confidence interval for a binomial proportion is (11.854, 13.385), which of the following would…

A:

Q: If n=11, ¯xx¯(x-bar)=32, and s=9, find the margin of error at a 98% confidence level

A:

Q: 11. A television station surveys 200 customers and finds that 23% of customers watch the evening…

A: Margin of error = z*√(pq/n) Where z= z value            n=no of customer            q=1-p…

Q: How large is the sample if the confidence level is 97%, Ɛ = 2.5%  and ρ = .35?

A:

Q: 4. The Department of the Treasury is interested in finding out what proportion of people support…

A: Given that  Population proportion p=15%=0.15 Margin of error =E =2%=0.02 95% confidence.  NOTE:-…

Q: A random sample of 600 voters in Centreville indicated that 90 of them believed their congressional…

A: Formula for confidence interval for population proportion : CI =p^ ± E  Where ,  p^ is sample…

Q: The statistics department is interested in estimating the proportion of students who have majored in…

A: Here we need to find the required sample size to estimate the proportion of students who majored…

Q: If n=12, ¯xx¯(x-bar)=44, and s=5, find the margin of error at a 99% confidence level

A: Given: margin of error for a 99% confidence interval. n=12 x¯(x-bar)=44 s=5

Q: In a previous election, the confidence interval for the proportion of likely voters who would vote…

A: given;confidence interval for the proportion;(0.4401, 0.5199)i.e. (p^-E, p^+E)where  p^ : point…

Q: 4. A researcher asks 600 people if they received a flu vaccine, and 65% said they did. What is the…

A:

Q: If n=13, = 42, and s=7, find the MARGIN OF ERROR at a 99% confidence level

A:

Q: If n=25, 7(x-bar)=48, and s=4, find the margin of error at a 80% confidence level

A: The sample size is 25, sample mean is 48, and sample standard deviation is 4. The degrees of freedom…

Q: NASA is interested in the true proportion of children who are interested in becoming astronauts. At…

A: Disclaimer: Since you have asked multiple questions, we will solve the first question for you. If…

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll,…

A: Solution: 12. From the given information, x=586 and n=1006.

Q: At one large college, 1867 out of the 2500 students surveyed said they plan to take another science…

A: The known values are, p^=1,867/2,500=0.7468, n=2,500. Using standard normal table, the critical…

Q: If n=12, ¯xx¯(x-bar)=48, and s=6, find the margin of error at a 98% confidence level

A: From the provided information, Sample size (n) = 12 Sample mean (x̄) = 48 Standard deviation (s) = 6…

Q: 3. Aresearcher wants to estimate the daily expenses of college students. He wants a 99% confidence…

A:

Q: Suppose a 90 percent confidence interval to estimate a population proportion was calculated from a…

A: Solution: From the given information, the sample proportion is 18% and a margin of error is 4…

Q: Construct a confidence interval for the population proportion p. n ? 144, x ? 86, 90% confidence

A: Given: Confidence level = 0.90 Sample size (n) = 144 x = 86 Sample proportion p^=xn=86144

Q: 19) A political survey had a margin of error of 4.25%. If the surveyor used a 90% confidence level…

A: Assume p-hat as 0.5, since no preliminary estimate is available.

Q: A magazine provided results from a poll of 500 adults who were asked to identify their favorite pie.…

A: Solution: Given information: n= 500 Sample size Here we need to interpret the meaning of each…

Q: Using your answers to parts (a) and (b), find a 95% confidence interval estimating the proportion of…

A: Here we need to construct a 95% confidence interval.

Q: The manager of a car company will select a random sample of its customers to create a 90 percent…

A: From the provided information, Confidence level = 90% Margin of error = 0.06

Q: Political Survey- A political analyst found that 43% of 300 randomly selected republican voters feel…

A: It is given that p hat is 0.43 and sample size (n) is 300. The confidence level is 0.95.

Q: If n=10, ¯xx¯(x-bar)=44, and s=8, find the margin of error at a 80% confidence level

A:

Q: Which confidence level will produce the widest confidence interval, given a sample proportion of…

A:

Q: If n=17, (x-bar)=44, and s=8, find the margin of error at a 95% confidence level

A: The sample mean is 44 and standard deviation is 8.

Q: In a​ poll, 69​% of the people polled answered yes to the question​ "Are you in favor of the death…

A: Given: Margin of errorE=0.02 Proportion of people who polled yes p^=0.69 The z value corresponding…

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll,…

A: Given, The sample proportion is,

Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…

A: Answer:

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.