Then we have from equation (1), -k-1 II Pi=1 k-1 nk-1 i=1 i=1 Pr (-1)*-(1) (-1)–1 (-1)k Yk=A - Where A is an arbitrary constant.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section: Chapter Questions
Problem 5T
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Explain the determine red

= bartleby
E Q&A
Math / Advanced Math / Q&A Library / (k) Yk+1+ Yk = (-1)*,
(k) Yk+1+ Yk =(-1)*,
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Step 2
Then we have from equation (1),
k-1
IIE Pi=1
Σ
nk-1
nk-1
(-1)
i
i=1
Pr
r=1
(-1)*-(1)
(-1)–1
(-1)*
Yk=A – S
2
Where A is an arbitrary constant.
Transcribed Image Text:= bartleby E Q&A Math / Advanced Math / Q&A Library / (k) Yk+1+ Yk = (-1)*, (k) Yk+1+ Yk =(-1)*, Get 24/7 homework help and experts with bartleby learn. Subscribe now! -> Step 2 Then we have from equation (1), k-1 IIE Pi=1 Σ nk-1 nk-1 (-1) i i=1 Pr r=1 (-1)*-(1) (-1)–1 (-1)* Yk=A – S 2 Where A is an arbitrary constant.
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