Theorem 14.If 0 < A+B+C+D< 1 and e‡ d, then the equilibrium point x given by (7) of Eq. (1) is global attractor.

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Theorem 14.If 0< A+B+ C+D<1 and e+ d, then
the equilibrium point x given by (7) of Eq.(1) is global
attractor.
Proof.We consider the following function
by
F(x, y, z, w) = Ax+By+Cz+ Dw+
(50)
(dy- ez)'
ez)?>bez and
where dy # ez, provided that B(dy -
C(dy- ez)? + bey>0. It is easy to verify the condition (i)
of Theorem 3. Let us now verify the condition (ii) of
Theorem 3 as follows:
[F(x, х, х, х) — х (х— X) —
b
K5x-
X
е —
- -
X
[Ks — 1] (е- d)
S x(e- d) [Ks – 1] – b \
2
e-d
1
(51)
[K5 – 1]
where K5 = (A+B+C+D). Since 0 < K5 < 1 and e+ d,
then we deduce from (51) that
[F(x, х, х, х) — х] (х— 3) <0.
(52)
According to Theorem 3, is global attractor. Thus, the
proof is now completed.O
On combining the two Theorems 4 and 14, we have the
result.
Transcribed Image Text:Theorem 14.If 0< A+B+ C+D<1 and e+ d, then the equilibrium point x given by (7) of Eq.(1) is global attractor. Proof.We consider the following function by F(x, y, z, w) = Ax+By+Cz+ Dw+ (50) (dy- ez)' ez)?>bez and where dy # ez, provided that B(dy - C(dy- ez)? + bey>0. It is easy to verify the condition (i) of Theorem 3. Let us now verify the condition (ii) of Theorem 3 as follows: [F(x, х, х, х) — х (х— X) — b K5x- X е — - - X [Ks — 1] (е- d) S x(e- d) [Ks – 1] – b \ 2 e-d 1 (51) [K5 – 1] where K5 = (A+B+C+D). Since 0 < K5 < 1 and e+ d, then we deduce from (51) that [F(x, х, х, х) — х] (х— 3) <0. (52) According to Theorem 3, is global attractor. Thus, the proof is now completed.O On combining the two Theorems 4 and 14, we have the result.
The objective of this article is to investigate some
qualitative behavior of the solutions of the nonlinear
difference equation
bxn-k
Xn+1 = Axn+ Bxŋ-k+Cxn-1+Dxn-o+
[dxn-k– exn-1]
(1)
n = 0,1,2, ...
where the coefficients A, B, C, D, b, d, e E (0,0), while
k, 1 and o are positive integers. The initial conditions
X-g,..., X_1,..., X_k ..., X_1, Xo are arbitrary positive real
numbers such that k <1< o. Note that the special cases
of Eq. (1) have been studied in [1] when B=C= D=0,
and k= 0,1= 1, b is replaced by – b and in [27] when
B=C= D=0, and k = 0, b is replaced by – b and in
[33] when B = C = D = 0, 1= 0 and in [32] when
A= C= D=0, 1=0, b is replaced by – b.
6.
•.•9
-
6.
|
(7)
[(A+B+C+ D) – 1] (e – d)
Let
us
now
introduce
a
continuous
function
F: (0, 0)* → (0, ) which is defined by
ai
bu
Theorem 3.[12]. Consider the difference equation (2).
Let xe I be an equilibrium point of Eq. (2). Suppose also
that
(i) F
is a nondecreasing function in each of its
arguments.
(ii) The function F satisfies the negative feedback
property
[F (x, X,х, х) — х (х- %) <0 for all х€1-{},
where I is an open interval of real numbers. Then x is
global attractor for all solutions of Eq. (2).
Transcribed Image Text:The objective of this article is to investigate some qualitative behavior of the solutions of the nonlinear difference equation bxn-k Xn+1 = Axn+ Bxŋ-k+Cxn-1+Dxn-o+ [dxn-k– exn-1] (1) n = 0,1,2, ... where the coefficients A, B, C, D, b, d, e E (0,0), while k, 1 and o are positive integers. The initial conditions X-g,..., X_1,..., X_k ..., X_1, Xo are arbitrary positive real numbers such that k <1< o. Note that the special cases of Eq. (1) have been studied in [1] when B=C= D=0, and k= 0,1= 1, b is replaced by – b and in [27] when B=C= D=0, and k = 0, b is replaced by – b and in [33] when B = C = D = 0, 1= 0 and in [32] when A= C= D=0, 1=0, b is replaced by – b. 6. •.•9 - 6. | (7) [(A+B+C+ D) – 1] (e – d) Let us now introduce a continuous function F: (0, 0)* → (0, ) which is defined by ai bu Theorem 3.[12]. Consider the difference equation (2). Let xe I be an equilibrium point of Eq. (2). Suppose also that (i) F is a nondecreasing function in each of its arguments. (ii) The function F satisfies the negative feedback property [F (x, X,х, х) — х (х- %) <0 for all х€1-{}, where I is an open interval of real numbers. Then x is global attractor for all solutions of Eq. (2).
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