Theorem 6 If (a1 + a3 + a5) > (a2 + a4) and (B1 + B3 + B5) > (B2 + B4) , then the necessary and sufficient condition for Eq.(1.1) to have positive so- lutions of prime period two is that the inequality [(A +1) ((B1 + B3 + B5) – (B2 + B4))] [(@1 + a3 + a5) - (a2 + a4)]? +4 [(a1 + a3 + as) – (a2 + a4)] [(B1 + B3 + B5) (a2 + a4) + A (B2 + B4) (a1 + a3 + a5)] > 0. (4.13)

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter2: Equations And Inequalities
Section2.7: More On Inequalities
Problem 54E
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Explain the determine green

Theorem 6 If (a1 + az + a5) > (a2 + a4) and (B1 + B3 + B5) > (B2 + B4),
then the necessary and sufficient condition for Eq. (1.1) to have positive so-
lutions of prime period two is that the inequality
[(А + 1) (B1 + вз + B:) — (В, + В4))] [(«1 + оз + о5) — (а2 + a4)|?
+4 [(a1 + a3 + a5) – (a2 + a4)] [(B1 + B3 + B5) (a2 + a4) + A (B2 + B4) (@1 + a3 + a5)] > 0.
(4.13)
is valid.
Transcribed Image Text:Theorem 6 If (a1 + az + a5) > (a2 + a4) and (B1 + B3 + B5) > (B2 + B4), then the necessary and sufficient condition for Eq. (1.1) to have positive so- lutions of prime period two is that the inequality [(А + 1) (B1 + вз + B:) — (В, + В4))] [(«1 + оз + о5) — (а2 + a4)|? +4 [(a1 + a3 + a5) – (a2 + a4)] [(B1 + B3 + B5) (a2 + a4) + A (B2 + B4) (@1 + a3 + a5)] > 0. (4.13) is valid.
The main focus of this article is to discuss some qualitative behavior of
the solutions of the nonlinear difference equation
a1Ym-1+ a2Ym-2 + a3Ym-3 + a4Ym-4+ a5Ym-5
Ym+1 =
Aym+
т 3D 0, 1, 2, ...,
В1ут-1 + В2ут-2 + Взут-3 + Влут-4 + B5ут-5
(1.1)
Transcribed Image Text:The main focus of this article is to discuss some qualitative behavior of the solutions of the nonlinear difference equation a1Ym-1+ a2Ym-2 + a3Ym-3 + a4Ym-4+ a5Ym-5 Ym+1 = Aym+ т 3D 0, 1, 2, ..., В1ут-1 + В2ут-2 + Взут-3 + Влут-4 + B5ут-5 (1.1)
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