Theorem 6. Let K be a field extension of a field F and let o which are algebric over F. Then F (a,, a,., a,) is a finite extension of sion of F.
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- If a0 in a field F, prove that for every bF the equation ax=b has a unique solution x in F. [Type here][Type here]Prove that if R and S are fields, then the direct sum RS is not a field. [Type here][Type here]Prove that any field that contains an intergral domain D must contain a subfield isomorphic to the quotient field Q of D.
- Suppose S is a subset of an field F that contains at least two elements and satisfies both of the following conditions: xS and yS imply xyS, and xS and y0S imply xy1S. Prove that S is a field. This S is called a subfield of F. [Type here][Type here]8. Prove that the characteristic of a field is either 0 or a prime.Since this section presents a method for constructing a field of quotients for an arbitrary integral domain D, we might ask what happens if D is already a field. As an example, consider the situation when D=5. a. With D=5, write out all the elements of S, sort these elements according to the relation , and then list all the distinct elements of Q. b. Exhibit an isomorphism from D to Q.
- Prove that if F is an ordered field with F+ as its set of positive elements, then F+nen+, where e denotes the multiplicative identity in F. (Hint: See Theorem 5.34 and its proof.) Theorem 5.34: Well-Ordered D+ If D is an ordered integral domain in which the set D+ of positive elements is well-ordered, then e is the least element of D+ and D+=nen+.Examples 5 and 6 of Section 5.1 showed that P(U) is a commutative ring with unity. In Exercises 4 and 5, let U={a,b}. Is P(U) a field? If not, find all nonzero elements that do not have multiplicative inverses. [Type here][Type here]True or False Label each of the following statements as either true or false. Every polynomial equation of degree over a field can be solved over an extension field of .