Theorem: for every real number x, x s |x]. Proof: If x 2 0, by definition |x| = x. Thus |x| > x. If x < 0, by definition |x| = -x. Since |x| = -x > 0 and O > x, \x| > x. Thus, Ix| 2 x. Q.E.D.

Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Gilbert, Linda, Jimmie
Chapter2: The Integers
Section2.1: Postulates For The Integers (optional)
Problem 28E
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Theorem: for every real number x, x < |x|.
Proof:
If x 2 0, by definition |x| = x. Thus |x| > x.
If x < 0, by definition |x| = -x.
Since |x| = -x > 0 and O > x, |x| > x.
Thus, |x| > x. Q.E.D.
Proof by Contradiction
O Proof by Contraposition
Proof by Cases
O Mathematical Induction
Transcribed Image Text:Theorem: for every real number x, x < |x|. Proof: If x 2 0, by definition |x| = x. Thus |x| > x. If x < 0, by definition |x| = -x. Since |x| = -x > 0 and O > x, |x| > x. Thus, |x| > x. Q.E.D. Proof by Contradiction O Proof by Contraposition Proof by Cases O Mathematical Induction
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