There are 35 ways of dividing the group into the two teams. As in Exercise 11, the number of ways 10 33 of choosing the 10 players for the first team so as to include both A and B is 8 The number of vays of choosing the 10 players for this team so as not to include either A or B (A and B will then be (33)
There are 35 ways of dividing the group into the two teams. As in Exercise 11, the number of ways 10 33 of choosing the 10 players for the first team so as to include both A and B is 8 The number of vays of choosing the 10 players for this team so as not to include either A or B (A and B will then be (33)
Chapter8: Sequences, Series,and Probability
Section8.7: Probability
Problem 9ECP: A random number generator selects two integers from 1 to 30. What is the probability that both...
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Transcribed Image Text:35
ways of dividing the group into the two teams. As in Exercise 11, the number of ways
There are
10
(33
of choosing the 10 players for the first team so as to include both A and B is
8
The number of
ways of choosing the 10 players for this team so as not to include either A or B (A and B will then be
33
together on the other team) is (). The probability we want is then
10
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