There are five activities on a project's critical path and they have standard deviations of 1, 1, 3, 5, 5 days. The standard deviation (indays) of the critical path is:OA. 8.8OB.9.8OC.7.8OD.4.6O.E. 10.2OF, 10.6WF2A Moving to another question will save this response.#320EF3D$4DOD000 F4RF%5F5TGMacBook Air^6....F6Y&7H◄◄F7U*► 118JF819KF9O)0F10« Question 30 of 42 > >>4)F11+ 11F12deleteDEB

Ans) Standard Deviations are 1,1,3,5,5 So, SD(1) = 1 SD (2) = 1 SD(3) = 3 SD (4) = 5 SD (5) = 5

Answered: There are five activities on a…

Practical Management Science

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In reference to the attached image and data below: Step A we learned: Critical Path = A, B, H, I, J; Project Time = 40 Weeks; Total Cost = 364,000 Step B we learned: To crash the critical path I would crash A by 1 week, B by 2 week, H by 2 week and C by 3 week. This would not alter the critical path, only the time line. Steps C we learned: Modeling uncertainty in activity times. In this case I would use the activity times and determine the Variances and the Standard Deviation. Using “best case” (x) and “worst case” (y) scenarios for activity times the formula’s would be (x-y)/6 and (x-y)^2/36. What are the final recommendations for this case?
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There are five activities on a project's critical path and they have standard deviations of 1, 1, 3, 5, 5 days. The standard deviation (in days) of the critical path is: OA. 8.8 OB.9.8 OC.7.8 COD.4.6 O.E. 10.2 OF 10.6