There are n focuses on an endless plane. The I-th point has facilitates (xi,yi) to such an extent that xi>0 and yi>0. The directions are not really integer. In one maneuver you play out the accompanying activities: pick two focuses an and b (a≠b); move point a from (
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Correct answer will be upvoted else downvoted.
There are n focuses on an endless plane. The I-th point has facilitates (xi,yi) to such an extent that xi>0 and yi>0. The directions are not really integer.
In one maneuver you play out the accompanying activities:
pick two focuses an and b (a≠b);
move point a from (xa,ya) to either (xa+1,ya) or (xa,ya+1);
move point b from (xb,yb) to either (xb+1,yb) or (xb,yb+1);
eliminate focuses an and b.
Notwithstanding, the move must be performed if there exists a line that goes through the new organizes of, another directions of b and (0,0).
If not, the move can't be performed and the focuses stay at their unique directions (xa,ya) and (xb,yb), individually.
Input
The main line contains a solitary integer n (1≤n≤2⋅105) — the number of focuses.
The I-th of the following n lines contains four integers
Output :In the primary line print a solitary integer c — the most extreme number of moves you can perform. Every one of the following c lines ought to contain a portrayal of a move: two integers an and b (1≤a,b≤n, a≠b) — the focuses that are taken out during the current move
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- Although the plot function is designed primarily for plotting standard xy graphs, it can be adapted for other kinds of plotting as well. b. Make a plot of the curve, which is defined parametrically by the equations x = 2cosθ + cos2θ, y = 2sinθ - sin2θ, where 0 < θ < 2π. Take a set of values of θ between zero and 2π and calculate x and y for each from the equations above, then plot y as a function of x. b. Taking this approach a step further, one can make a polar plot r = f(θ) for some function f by calculating r for a range of values of θ and then converting r and θ to Cartesian coordinates using the standard equations x = r cosθ, y = r sinθ. Use this method to make a plot of the function r = ecosθ – 2 cos(4θ) + sin5 (θ/12) in the range 0 <= θ <= 24π. use python code to answer the highlight oneAnswer the following: This problem exercises the basic concepts of game playing, using tic-tac-toe (noughts and crosses) as an example. We define Xn as the number of rows, columns, or diagonals with exactly n X’s and no O’s. Similarly, On is the number of rows, columns, or diagonals with just n O’s. The utility function assigns +1 to any position with X3=1 and −1 to any position with O3=1. All other terminal positions have utility 0. For nonterminal positions, we use a linear evaluation function defined as Eval(s)=3X2(s)+X1(s)−(3O2(s)+O1(s)). a. Show the whole game tree starting from an empty board down to depth 2 (i.e., one X and one O on the board), taking symmetry into account. b. Mark on your tree the evaluations of all the positions at depth 2. c .Using the minimax algorithm, mark on your tree the backed-up values for the positions at depths 1 and 0, and use those values to choose the best starting move. Provide original solutions including original diagram for part a!Answer the following: This problem exercises the basic concepts of game playing, using tic-tac-toe (noughts and crosses) as an example. We define Xn as the number of rows, columns, or diagonals with exactly n X’s and no O’s. Similarly, On is the number of rows, columns, or diagonals with just n O’s. The utility function assigns +1 to any position with X3=1 and −1 to any position with O3=1. All other terminal positions have utility 0. For nonterminal positions, we use a linear evaluation function defined as Eval(s)=3X2(s)+X1(s)−(3O2(s)+O1(s)). a. Show the whole game tree starting from an empty board down to depth 2 (i.e., one X and one O on the board), taking symmetry into account. b. Mark on your tree the evaluations of all the positions at depth 2. c .Using the minimax algorithm, mark on your tree the backed-up values for the positions at depths 1 and 0, and use those values to choose the best starting move. Provide original solution!
- This problem exercises the basic concepts of game playing, using tic-tac-toe (noughtsand crosses) as an example. We define Xn as the number of rows, columns, or diagonals with exactly n X’s and no O’s. Similarly, On is the number of rows, columns, or diagonals with just n O’s. The utility function assigns +1 to any position with X3 = 1 and −1 to any position with O3 = 1. All other terminal positions have utility 0. For nonterminal positions, we use a linear evaluation function defined as Eval (s) = 3X2(s)+X1(s)−(3O2(s)+O1(s))."Mark on your tree the evaluations of all the positions at depth 2."Correct answer will be upvoted else downvoted. puzzle comprises of an upstanding board with n lines and m sections of cells, some vacant and some loaded up with squares of sand, and m non-negative integers a1,a2,… ,am (0≤ai≤n). In this adaptation of the issue, simulated intelligence will be equivalent to the number of squares of sand in segment I. At the point when a cell loaded up with a square of sand is upset, the square of sand will tumble from its cell to the sand counter at the lower part of the section (every segment has a sand counter). While a square of sand is falling, different squares of sand that are adjoining anytime to the falling square of sand will likewise be upset and begin to fall. In particular, a square of sand upset at a cell (i,j) will go through all cells underneath and including the cell (i,j) inside the section, upsetting all nearby cells en route. Here, the cells adjoining a cell (i,j) are characterized as (i−1,j), (i,j−1), (i+1,j), and (i,j+1) (in…Suppose we use the following KB (where x, y, z are variables and r1, r2, r3, goal are constants) to determine whether a particular robot can score. (a) Open(x) ∧ HasBall(x) → CanScore(x)(b) Open(x) ∧ CanAssist(y, x) ∧ HasBall(y) → CanScore(x) (c) PathClear(x,y) → CanAsist(x,y)(d) PathClear(x,z) ∧ CanAssist(z,y) → CanAssist(x,y) (e) PathClear(x,goal) → Open(x)(f) PathClear(y,x) → PathClear(x,y) (g) HasBall(r3)(h) PathClear(r1,goal) (i) PathClear(r2,r1) (j) PathClear(r3,r2) (k) PathClear(r3,goal)
- Suppose we use the following KB (where x, y, z are variables and r1, r2, r3, goal are constants) to determine whether a particular robot can score. (a) Open(x) ∧ HasBall(x) → CanScore(x)(b) Open(x) ∧ CanAssist(y, x) ∧ HasBall(y) → CanScore(x) (c) PathClear(x,y) → CanAsist(x,y)(d) PathClear(x,z) ∧ CanAssist(z,y) → CanAssist(x,y) (e) PathClear(x,goal) → Open(x)(f) PathClear(y,x) → PathClear(x,y) (g) HasBall(r3)(h) PathClear(r1,goal) (i) PathClear(r2,r1) (j) PathClear(r3,r2) (k) PathClear(r3,goal) Intuitively, CanScore(x) means x can score on goal. CanAssist(x, y) means there exists some series of passes that can get the ball from x to y. Open(x) means x can shoot on goal directly. And P athClear(x, y) means the path between x and y is clear. Provide a SLD-derivation for the query CanScore(x) in which the answer provided is r1. Provide a SLD-derivation for the query CanScore(x) in which the answer provided is r3. How many “distinct” derivations (i.e., involving different…In the context of evolutionary computing the goal function is known as the fitnessfunction and the problem is to maximize it. The typical formulation has to be changedin a simple way.min f (x) = − max[− f (x)] (4.9)Another requirement is that the goal function is positive.Phenotype evolution treats x as a phenotype and the goal function as the fitnessfunction. The typical framework for the method is as follows:Correct answer will be upvoted else Multiple Downvoted. Computer science. You are given an integer n (n>1). Your assignment is to find a succession of integers a1,a2,… ,ak with the end goal that: every simulated intelligence is completely more prominent than 1; a1⋅a2⋅… ⋅ak=n (I. e. the result of this grouping is n); ai+1 is separable by simulated intelligence for every I from 1 to k−1; k is the most extreme conceivable (I. e. the length of this grouping is the greatest conceivable). In case there are a few such groupings, any of them is adequate. It tends to be demonstrated that somewhere around one substantial grouping consistently exists for any integer n>1. You need to answer t autonomous experiments. Input The primary line of the input contains one integer t (1≤t≤5000) — the number of experiments. Then, at that point, t experiments follow. The main line of the experiment contains one integer n (2≤n≤1010). It is ensured that the amount of n…
- Suppose we use the following KB (where x,y,z are variables and r1, r2, r3, goal are constants) to determine whether a particular robot can score a) Open(x) ∧ HasBall(x) -> CanScore(x) b) Open(x) ∧ CanAssist(y,x) ∧ HasBall(y) -> CanScore(x) c) PathClear(x,y) -> CanAssist(x,y) d) PathClear(x,z) ∧ CanAssist(z,y) -> CanAssist(x,y) e) PathClear(x,goal) -> Open(x) f) PathClear(y,x) -> PathClear(x,y) g) HasBall(r3) h) PathClear(r1, goal) i) PathClear(r2, r1) j) PathClear(r3, r2) k) PathClear(r3, goal) Intuitively, CanScore(x) means x can score on goal. CanAssist(x,y) means there exists some series of passes that can get the ball from x to y. Open(x) means x can shoot on goal directly. And PathClear(x,y) means the path between x and y is clear. Provide a SLD-derivation for the query CanScore(x) in which the answer provided is r1. Provide a SLD-derivation for the query CanScore(x) in which the answer provided is r3. How many "distinct" derivations (i.e., involving different…Correct answer will be upvoted else Multiple Downvoted. Computer science. Gildong has a square board comprising of n lines and n sections of square cells, each comprising of a solitary digit (from 0 to 9). The cell at the j-th section of the I-th line can be addressed as (i,j), and the length of the side of every cell is 1. Gildong prefers enormous things, so for every digit d, he needs to find a triangle with the end goal that: Every vertex of the triangle is in the focal point of a cell. The digit of each vertex of the triangle is d. Somewhere around one side of the triangle is corresponding to one of the sides of the board. You might expect that a side of length 0 is corresponding to the two sides of the board. The space of the triangle is boosted. Obviously, he can't simply be content with tracking down these triangles with no guarantees. Along these lines, for every digit d, he will change the digit of precisely one cell of the board to d, then, at that point, track…Correct answer will be upvoted else downvoted. Computer science. way from block u to obstruct v is a grouping u=x0→x1→x2→⋯→xk=v, where there is a street from block xi−1 to hinder xi for each 1≤i≤k. The length of a way is the amount of lengths over all streets in the way. Two ways x0→x1→⋯→xk and y0→y1→⋯→yl are unique, if k≠l or xi≠yi for some 0≤i≤min{k,l}. Subsequent to moving to another city, Homer just recalls the two exceptional numbers L and R yet fails to remember the numbers n and m of squares and streets, separately, and how squares are associated by streets. Be that as it may, he accepts the number of squares ought to be no bigger than 32 (in light of the fact that the city was little). As the dearest companion of Homer, if it's not too much trouble, let him know whether it is feasible to see as a (L,R)- constant city or not. Input The single line contains two integers L and R (1≤L≤R≤106). Output In case it is difficult to track down a (L,R)- consistent city…