Q1. a)There are three forces acting on an object, that is, F = (2,5, 6)N, F, =(-5, –9,6) N and F, = (12,8,–3)N.(i)What is the resultant force on the object?(ii) What is the angle between F, and F,?A conductor lies in a magnetic field. The current flowing through theconductor is Ī = (5,9,4). The magnetic flux density is B = (-2,4,6).Calculate the electromagnetic force acting on the conductor by F = I × B.b)c)Solve the following set of simultaneous equations using matricesЗх + у — 2z %3D45х — 3z 3D 6-x + 2y + 2z = 3

There are three forces acting on an object, that is, F, = (2,5, 6)N, F, = (-5,–9,6) N and F = (12,8, –3)N. Q1. a) (i) What is the resultant force on the object? (ii) What is the angle between F, and F,? A conductor lies in a magnetic field. The current flowing through the b) conductor is Ī = (5,9,4). The magnetic flux density is B = (-2,4,6) . Calculate the electromagnetic force acting on the conductor by F = Ì × B.

There are three forces acting on an object, that is, F, = (2,5, 6)N, F, = (-5,–9,6) N and F = (12,8, –3)N. Q1. a) (i) What is the resultant force on the object? (ii) What is the angle between F, and F,? A conductor lies in a magnetic field. The current flowing through the b) conductor is Ī = (5,9,4). The magnetic flux density is B = (-2,4,6) . Calculate the electromagnetic force acting on the conductor by F = Ì × B.

Refrigeration and Air Conditioning Technology (MindTap Course List)

8th Edition

ISBN:9781305578296

Author:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson

Publisher:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson

Chapter2: Matter And Energy

Section: Chapter Questions

Problem 25RQ: How many watts of electrical energy are equal to 1 hp?

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