There is 2.878 x 10-4 mol of an unidentified gaseous substance effuses through a tiny hole in 98.9 s. Under identical conditions, 1.740 x 10-4 mol of argon gas takes 61.5 s to effuse. What is the molar mass of the unidentified substance (in g/mol)? What is the molecular formula of the substance? Under identical conditions, how many moles of ethene (C2H4) gas would effuse in 91.0 s?

Q: It took 4.5 min for 1.0 L helium to effuse through a porous barrier. How long will it take for 1.0 L…

A: For any certain gas, the rate of effusion is equivalent to the gas's volume that is undergoing the…

Q: 2. 2.07x10-3 mol of an unknown gas effuses through a tiny hole in 217.25 s. Under identical…

A: Rate of effusion :- The number of moles (n) of a gas effused per unit time (t) is called rate of…

Q: It takes 24 hours for 1.5 L sample of carbon monoxide, CO, to effuse through a pinhole. Under the…

A: According to Graham's law of effusion, the rate of effusion of a gas is inversely proportional to…

Q: A gas sample is observed to exert a pressure of 600 torr when confined to a 10.0-L vessel at…

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Q: Methane gas, CH4, effuses through a barrier at a rate of 0.862 mL/minute. If an unknown gas effuses…

A:

Q: The rate of effusion of N, to an unknown gas is 0.756, what is the molar mass of the other gas?…

A: We have to find mass of unknown

Q: A 6.0-L flask contains a mixture of methane (CH4), argon, and helium at 45oC and 1.75 atm. If the…

A: Given information, A 6.0-L flask contains a mixture of methane (CH4), argon, and helium at 45oC and…

Q: It takes 169 s for an unknown gas to effuse through a porous wall and 97 s for the same volume of…

A: It is given that an unknown gas takes 167 seconds to effuse and nitrogen gas takes 97 seconds to…

Q: At what pressure does the mean free path of Argon at 298K become comparable to the size of a 1.000 L…

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Q: Gas X effuses through a pinhole at a rate of 4.73 × 104mol/s. Methane gas, CH4(g), effuses through…

A:

Q: How can comparing the rates of effusion of gases X and Y allow the molar mass of Y to be calculated?…

A: Grahams’s Law of effusion states that the rate of effusion of a gas is inversely proportional to…

Q: How long, in minutes, will it take 10.0 ml of H2 gas to effuse through a porous barrier if it has…

A: The time is to be calculated

Q: A gas mixture contains each of the following gases at the indicated partial pressures N 2 ,216 torr;…

A: Partial pressure of N2 = 216 torr ...Or  because 1 atm = 760 torr  ...so,  = 216 torr × (1 atm / 760…

Q: In 2.00 min, 29.7 mL of He effuse through a small hole. Under the same conditions of pressure and…

A: The term number of moles of a given chemical species can be defined as the ratio of its mass to the…

Q: It takes 161 s for an unknown gas to effuse through a porous wall and 97 s for the same volume of N2…

A: rate of effusion is inversely proportional to the  under root of molecular mass. And directly…

Q: At a certain temperature and pressure, the rate of effusion of N2 gas is 30.0 mL/minute. What is the…

A: According to Graham's law , the effusion rate of any gas is inversely proportional to the square…

Q: A sample of an unkown gas effuses in 17.42 min. An equal volume of hydrogen gas in the sam apparatus…

A: Given that: Time of effusion of unknown gas = 17.42 min Time of effusion of Hdrogen gas = 2.15 min…

Q: Suppose a 185 gram sample of hydrogen reacts as follows: 2 NO2(g) + 7 H2(g) → 2 NH3 (g) + 4 H2O(g)…

A: The balanced reaction taking place is given as, => Given: Mass of H2 reacting = 185 g. Volume of…

Q: 2.076×10-4 mol of an unidentified gaseous substance effuses through a tiny hole in 92.9 s. A) Under…

A: According to Graham's Law of diffusion, the rate of diffusion of a gas through a narrow space is…

Q: The rate of effusion of He gas through a porous barrier is observed to be 4.02x10^-4 mol/h. Under…

A: given:  molar mass of He = 4.002 g/mol = MHe rate of effusion for He = 4.02 x 10-4 mol/h = RHe molar…

Q: The rate of effusion of a particular gas was measured and found to be 24.0 mL/min. Under the same…

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Q: 2.07x103 mol of an unknown gas effuses through a tiny hole in 217.25 s. Under identical conditions,…

A: The rate of effusion of the gaseous substance is inversely proportional to the square root of its…

Q: Under identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through…

A:

Q: A sample of neon gas effuses through a pinhole at a rate of 0.46 mL/s. What will be the rate of…

A: Graham’s law of effusion is given by,

Q: Suppose a 185 gram sample of hydrogen reacts as follows: 2 NO2 (g) + 7 H2 (g) → 2 NH3 (g) + 4 H20(g)…

A: 8.7 ) First we calculate moles of hydrogen gas , then we would use stoichiometry relation to…

Q: Under identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through…

A:

Q: Under identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through…

A: To Calculate molar mass of unknown gas , we would use the relation between rate of effusion and…

Q: the same barrier. The molar mass of the unknown gas is ____g/mol.

A: We have to find molar mass of the unknown gas

Q: a) 1.488×10-4 mol of an unidentified gaseous substance effuses through a tiny hole in 81.2 s. Under…

A: Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: A mixture of N2 and CO2 gases has an average molar mass of 32.8 g/mol. What is the partial pressure…

A:

Q: A sample of N2 gas is contaminated with a gas (A) of unknown molar mass. The partial pressure of…

A: We have to predict molar mass of gas A.

Q: What is the molar mass of the uranium fluoride?

A:

Q: The rate of effusion of sulfur dioxide through a hole is 4.48 ml per second. What is the molar mass…

A: The rate of effusion of the gas and the molar mass of gas are inversely related that mean lower the…

Q: 2.07x10-3 mol of an unknown gas effuses through a tiny hole in 217.25 s. Under identical conditions,…

A: (a) Given  moles of unkown gas =2.07×10-3molTime of effusion =217.25 smolar mass =m gm/mol   moles…

Q: A sample of SO2 gas is observed to effuse through a pourous barrier in 3.70 minutes. Under the same…

A: Given- Rate of effusion of SO2 gas = 3.70 min Rate of effusion of unknown gas = 1.66 min   To find-…

Q: It takes 110. seconds for a sample of carbon dioxide to effuse through a porous plug and 275 seconds…

A: The answer to the following question is-

Q: The rate at which argon, (Ar) effuses through pinhole is 4.5 ml/min. At what rate will the hydrogen…

A: Relation between rate of effusion and molar mass of gases: R2/R1 = (M1/M2)1/2 Where,  R1 =  rate of…

Q: Under identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through…

A: Given: The volume of O2 effused = 6.15 mL The volume of the unknown gas effused at the same time =…

Q: 1.734×10-4 mol of an unidentified gaseous substance effuses through a tiny hole in 93.2 s. A) Under…

A: According to Graham's law of effusion, the rate of effusion of a gas is inversely proportional to…

Q: 4. A monatomic unknown gas is found to effuse at a rate that is 0.5651 times that of chlorine gas…

A:

Q: A sample of unknown gas and N2 are allowed to effuse from the same apparatus. The unknown gas…

A: Given, Rate of effusion of N2 = 9.55 m/s Rate of effusion of unknown gas = 5.45 m/s Molar mass of N2…

Q: A sample of N2O effuses from a container in 42 seconds. How long will it take the same amount of…

A: the rate of effusion is guided by many factors.rateN2OrateI2=MI2MN2Owhen container is same, the…

Q: A study of the effects of certain gases on the plant growth requires a synthetic atmosphere composed…

A: The mole percentage of each gas is the percentage of the number of moles of each gas in the…

Q: The label on a cylinder of a noble gas became illegible, so a student allowed some of the gas to…

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Q: The rate of effusion of H2 gas through a porous barrier is observed to be 8.50x10(-4) mol/h. Under…

A: The Graham’s law of effusion states that “the rate of effusion of a gas is inversely proportional to…

Q: .Calculate the total pressure of a mixture of gases in atm., each of which exerts the given partial…

A: We are authorized to answer one question at a time. Since you have not mentioned which question you…

Q: Use Graham's law of effusion to calculate molar mass. A sample of argon, Ar, effuses through a small…

A: Answer:- This question is answered by using the concept of determination of rate of effusion which…

Q: the air that fills the airbags instead of automobiles is generally nitrogen produced by complicated…

A: According to the given information, one mole of nitrogen gas is produced by one mole of sodium…

Q: Gaseous neon is observed to effuse through a tiny hole at a rate of 1.90 cm3/min. An unknown gas is…

A: According to Graham's law of effusion, rate of effusion is inversely proportional to molar mass of…

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.