Therefore, sin () -- sin (a)- K please follow the eample and complete sin tam ( - ) - en ( - #*) - cot

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.4: Values Of The Trigonometric Functions
Problem 42E
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only need D and E  and F answered

1. Complete the table for the sine, cosine and tangent for the special angles in quadrant I. Keep your answer with radical if any.
3
sin x
cos a
tan a
1
1
1
and the table above to complete the table for cotangent, secant and cosecant for the special angles in quadrant I. Keep your answer with radical if any.
cos E
2. Use the identities cot r
sec x =
csc a =
sin x
tan a
cos a
sin a
cot a
sec a
Csc a
3. Determine the sign (positive or negative) of each trigonometric function for the angles in various quadrants. Put + or - to complete the table:
sin z
Cos a
tan x
cot a
sec x
Csc x
QI
QI
QII
QIV
197
4 Follow the example and find the exact value for the given trigonometric functions For example sin
i) the reference angle is
6
i) sin () =
197
iii)
is in quadrant III; hence, sine is negative
6
197
= - sin
1
Therefore, sin
2
Now, please follow the example and complete:
11T
a)
sin
(學)
157
b)
Cos
137
c)
tan
3
d)
cot (- *)
6
237
e)
sec
19T
CSC
Transcribed Image Text:1. Complete the table for the sine, cosine and tangent for the special angles in quadrant I. Keep your answer with radical if any. 3 sin x cos a tan a 1 1 1 and the table above to complete the table for cotangent, secant and cosecant for the special angles in quadrant I. Keep your answer with radical if any. cos E 2. Use the identities cot r sec x = csc a = sin x tan a cos a sin a cot a sec a Csc a 3. Determine the sign (positive or negative) of each trigonometric function for the angles in various quadrants. Put + or - to complete the table: sin z Cos a tan x cot a sec x Csc x QI QI QII QIV 197 4 Follow the example and find the exact value for the given trigonometric functions For example sin i) the reference angle is 6 i) sin () = 197 iii) is in quadrant III; hence, sine is negative 6 197 = - sin 1 Therefore, sin 2 Now, please follow the example and complete: 11T a) sin (學) 157 b) Cos 137 c) tan 3 d) cot (- *) 6 237 e) sec 19T CSC
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