Thermal conductivity k (9%) Problem 10: Suppose a house's walls are 13 cm thick and and have an average thermal conductivity twice that of glass wool. Substance (J/s•m C) Glass wool Wool 0.042 0.04 Glass 0.84 Human body Ceramic Wood Air Fatty tissue 0.2 0.84 0.08-0.16 0.023 0.2 Styrofoam 0.010 ©theexpertta.com 50% Part (a) Calculate the rate of heat conduction, in watts, through the house's walls. Assume there are no windows or doors. The surface area of the walls is 140 m² and their inside surface is at 18.5°C, while their outside surface is at 5.15°C. Grade Summary Q'At = Deductions 0% 100% Potential sin() cos() tan() 9 HOME Submissions Attempts remaining: 10 (0% per attempt) detailed view cotan() asin() acos() E 4 5 atan() acotan() sinh() cosh() tanh() cotanh() END ODegrees O Radians VO BACKSPACE DEL CLEAR Submit Hint Feedback I give up! Hints: 0% deduction per hint. Hints remaining:1 Feedback: 0% deduction per feedback. 50% Part (b) How many 1.00-kW room heaters would be needed to balance the heat transfer due to conduction? Round your answer to the nearest integer value. 63 2. 1.

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Chapter11: Energy In Thermal Processes
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(9%) Problem 10: Suppose a house's walls are 13 cm thick and and have an average thermal
conductivity twice that of glass wool.
Thermal conductivity k
(J/s• m C)
Substance
Glass wool
Wool
0.042
0.04
Glass
0.84
Human body
Ceramic
Wood
Air
Fatty tissue
Styrofoam
0.2
0.84
0.08-0.16
0.023
0.2
0.010
©theexpertta.com
50% Part (a) Calculate the rate of heat conduction, in watts, through the house's walls. Assume there are no windows or doors. The surface area of the
walls is 140 m² and their inside surface is at 18.5°C, while their outside surface is at 5.15°C.
Grade Summary
Deductions
Potential
QAt =
0%
100%
*( 7 8 9
E 4
sin()
Submissions
cos()
asin()
tan()
HOME
cotan()
Attempts remaining:
(0% per attempt)
detailed view
acos()
5
6
atan()
acotan()
sinh()
cotanh()
1
2
cosh()
tanh()
- 0
END
Degrees
Radians
VO BACKSPACE
DEL
CLEAR
Submit
Hint
Feedback
I give up!
Hints: 0% deduction per hint. Hints remaining: 1
Feedback: 0% deduction per feedback.
50% Part (b) How many 1.00-kW room heaters would be needed to balance the heat transfer due to conduction? Round your answer to the nearest integer
value.
Transcribed Image Text:(9%) Problem 10: Suppose a house's walls are 13 cm thick and and have an average thermal conductivity twice that of glass wool. Thermal conductivity k (J/s• m C) Substance Glass wool Wool 0.042 0.04 Glass 0.84 Human body Ceramic Wood Air Fatty tissue Styrofoam 0.2 0.84 0.08-0.16 0.023 0.2 0.010 ©theexpertta.com 50% Part (a) Calculate the rate of heat conduction, in watts, through the house's walls. Assume there are no windows or doors. The surface area of the walls is 140 m² and their inside surface is at 18.5°C, while their outside surface is at 5.15°C. Grade Summary Deductions Potential QAt = 0% 100% *( 7 8 9 E 4 sin() Submissions cos() asin() tan() HOME cotan() Attempts remaining: (0% per attempt) detailed view acos() 5 6 atan() acotan() sinh() cotanh() 1 2 cosh() tanh() - 0 END Degrees Radians VO BACKSPACE DEL CLEAR Submit Hint Feedback I give up! Hints: 0% deduction per hint. Hints remaining: 1 Feedback: 0% deduction per feedback. 50% Part (b) How many 1.00-kW room heaters would be needed to balance the heat transfer due to conduction? Round your answer to the nearest integer value.
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