The Unknown Liquid is Ethanol (CH3CH2OH). The "accepted" Heat of Vaporization (∆Hvap) can be calculated (at 25oC, 1 atm) using the Heats of Formation (∆Hof) of the compound in its liquid state (∆Hof)Liq and its gas state (∆Hof)gas. The Heats of Formation (∆Hof) for Ethanol (the unknown) in its liquid and gas states are: liquid state (∆Hof)Liq = -277.7 kJ/mol gas state (∆Hof)gas= -235.1 kJ/mol Calculate theHeat of Vaporization (∆Hvap) (at 25oC, 1 atm) using these Heats of Formation (∆Hof) for Ethanol.
The Unknown Liquid is Ethanol (CH3CH2OH). The "accepted" Heat of Vaporization (∆Hvap) can be calculated (at 25oC, 1 atm) using the Heats of Formation (∆Hof) of the compound in its liquid state (∆Hof)Liq and its gas state (∆Hof)gas. The Heats of Formation (∆Hof) for Ethanol (the unknown) in its liquid and gas states are: liquid state (∆Hof)Liq = -277.7 kJ/mol gas state (∆Hof)gas= -235.1 kJ/mol Calculate theHeat of Vaporization (∆Hvap) (at 25oC, 1 atm) using these Heats of Formation (∆Hof) for Ethanol.
Chapter6: Thermochemistry
Section: Chapter Questions
Problem 95AE: It has been determined that the body can generate 5500 kJ of energy during one hour of strenuous...
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4) The Unknown Liquid is Ethanol (CH3CH2OH).
The "accepted" Heat of Vaporization (∆Hvap) can be calculated (at 25oC, 1 atm) using the Heats of Formation (∆Hof) of the compound in its liquid state (∆Hof)Liq and its gas state (∆Hof)gas.
- The Heats of Formation (∆Hof) for Ethanol (the unknown) in its liquid and gas states are:
- liquid state (∆Hof)Liq = -277.7 kJ/mol
- gas state (∆Hof)gas= -235.1 kJ/mol
- Calculate theHeat of Vaporization (∆Hvap) (at 25oC, 1 atm) using these Heats of Formation (∆Hof) for Ethanol.
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