this is a TCP python socket server. this code have been used by so many people and someone asked me to make it unique, so what can i change to make it unique without breaking the code ? first file is server.py, and second one is client.py. import socket import sys import os from util import send_file, recv_file, send_listing, recv_listing script_dir = os.path.dirname(__file__) rel_path = "server/" abs_file_path = os.path.join(script_dir, rel_path) srv_sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM) try: srv_sock.bind(("0.0.0.0", int(sys.argv[1]))) srv_sock.listen(5) except Exception as e: print(e) exit(1) while True: try: print("Waiting for new client... ") cli_sock, cli_addr = srv_sock.accept() cli_addr_str = str(cli_addr) print("Client " + cli_addr_str + " connected. Now chatting...") commandList = cli_sock.recv(1024) command = commandList.decode().split(" ", 1) if (command[0] == "list"): send_listing(cli_sock) else: textfileName = command[1] fileName=abs_file_path+textfileName if (command[0] == "put"): recv_file(fileName,cli_sock) elif (command[0] == "get"): send_file(fileName,cli_sock) finally: cli_sock.close() exit(0) import socket import sys import os from util import send_file, recv_file, send_listing, recv_listing script_dir = os.path.dirname(__file__) rel_path = "client/" abs_file_path = os.path.join(script_dir, rel_path) cli_sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM) srv_addr = (sys.argv[1], int(sys.argv[2])) try: cli_sock.connect(srv_addr) print("Connected. Now chatting...") except Exception as e: print(e) exit(1) try: if(len(sys.argv)==4): user_input = sys.argv[3]+" " elif(len(sys.argv)==5): user_input = sys.argv[3]+" "+sys.argv[4] command = user_input.split(" ", 1) if (command[0] == "list"): cli_sock.sendall(str.encode(user_input)) li=recv_listing(cli_sock) print(" ".join(li)) else: filename = abs_file_path+command[1] if (command[0] == "put"): cli_sock.sendall(str.encode(user_input)) send_file(filename,cli_sock) elif (command[0] == "get"): cli_sock.sendall(str.encode(user_input)) recv_file(filename,cli_sock) finally: cli_sock.close() exit(0)

this is a TCP python socket server. this code have been used by so many people and someone asked me to make it unique, so what can i change to make it unique without breaking the code ? first file is server.py, and second one is client.py. import socket import sys import os from util import send_file, recv_file, send_listing, recv_listing script_dir = os.path.dirname(file) rel_path = "server/" abs_file_path = os.path.join(script_dir, rel_path) srv_sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM) try: srv_sock.bind(("0.0.0.0", int(sys.argv[1]))) srv_sock.listen(5) except Exception as e: print(e) exit(1) while True: try: print("Waiting for new client... ") cli_sock, cli_addr = srv_sock.accept() cli_addr_str = str(cli_addr) print("Client " + cli_addr_str + " connected. Now chatting...") commandList = cli_sock.recv(1024) command = commandList.decode().split(" ", 1) if (command[0] == "list"): send_listing(cli_sock) else: textfileName = command[1] fileName=abs_file_path+textfileName if (command[0] == "put"): recv_file(fileName,cli_sock) elif (command[0] == "get"): send_file(fileName,cli_sock) finally: cli_sock.close() exit(0) import socket import sys import os from util import send_file, recv_file, send_listing, recv_listing script_dir = os.path.dirname(file) rel_path = "client/" abs_file_path = os.path.join(script_dir, rel_path) cli_sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM) srv_addr = (sys.argv[1], int(sys.argv[2])) try: cli_sock.connect(srv_addr) print("Connected. Now chatting...") except Exception as e: print(e) exit(1) try: if(len(sys.argv)==4): user_input = sys.argv[3]+" " elif(len(sys.argv)==5): user_input = sys.argv[3]+" "+sys.argv[4] command = user_input.split(" ", 1) if (command[0] == "list"): cli_sock.sendall(str.encode(user_input)) li=recv_listing(cli_sock) print(" ".join(li)) else: filename = abs_file_path+command[1] if (command[0] == "put"): cli_sock.sendall(str.encode(user_input)) send_file(filename,cli_sock) elif (command[0] == "get"): cli_sock.sendall(str.encode(user_input)) recv_file(filename,cli_sock) finally: cli_sock.close() exit(0)

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Question

this is a TCP python socket server.

this code have been used by so many people and someone asked me to make it unique, so what can i change to make it unique without breaking the code ? first file is server.py, and second one is client.py.

import socket

import sys

import os

from util import send_file, recv_file, send_listing, recv_listing

script_dir = os.path.dirname(__file__)

rel_path = "server/"

abs_file_path = os.path.join(script_dir, rel_path)

srv_sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)

try:

srv_sock.bind(("0.0.0.0", int(sys.argv[1])))

srv_sock.listen(5)

except Exception as e:

print(e)

exit(1)

while True:

try:

print("Waiting for new client... ")

cli_sock, cli_addr = srv_sock.accept()

cli_addr_str = str(cli_addr)

print("Client " + cli_addr_str + " connected. Now chatting...")

commandList = cli_sock.recv(1024)

command = commandList.decode().split(" ", 1)

if (command[0] == "list"):

send_listing(cli_sock)

else:

textfileName = command[1]

fileName=abs_file_path+textfileName

if (command[0] == "put"):

recv_file(fileName,cli_sock)

elif (command[0] == "get"):

send_file(fileName,cli_sock)

finally:

cli_sock.close()

exit(0)

import socket

import sys

import os

from util import send_file, recv_file, send_listing, recv_listing

script_dir = os.path.dirname(__file__)

rel_path = "client/"

abs_file_path = os.path.join(script_dir, rel_path)

cli_sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)

srv_addr = (sys.argv[1], int(sys.argv[2]))

try:

cli_sock.connect(srv_addr)

print("Connected. Now chatting...")

except Exception as e:

print(e)

exit(1)

try:

if(len(sys.argv)==4):

user_input = sys.argv[3]+" "

elif(len(sys.argv)==5):

user_input = sys.argv[3]+" "+sys.argv[4]

command = user_input.split(" ", 1)

if (command[0] == "list"):

cli_sock.sendall(str.encode(user_input))

li=recv_listing(cli_sock)

print(" ".join(li))

else:

filename = abs_file_path+command[1]

if (command[0] == "put"):

cli_sock.sendall(str.encode(user_input))

send_file(filename,cli_sock)

elif (command[0] == "get"):

cli_sock.sendall(str.encode(user_input))

recv_file(filename,cli_sock)

finally:

cli_sock.close()

exit(0)

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