//This method is passed in 2 Strings and returns the longer public static String longerString(String a, String b) {
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- Method called reverse that reverses a string passed to this method as a parameter and returns the reversed string. Eg reverse(“string”) should return “gnirts”. Print out the reversed string in your main method. Hint: Use CharAt or Substring methods from the String Class./*** Returns a new string that is filled with length number of BLANK characters (e.g., initGuess(5, "$") would return the String "$$$$$""* @param length* @param BLANK* @return a new string that is filled with length number of blank characters* */public static String initGuess(int length, char BLANK) {return "string";}Write a method that finds the number of occurrences of a specified character in a string using thefollowing header:public static int countLetter(String str, char ch)Write a test program that prompts the user to enter a word and a letter of the alphabet. Theprogram should then count and display the number of occurrences of the letter in the word. Asample dialog for the program is shown below:
- public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current string.This problem is an exercise in Java string manipulation. For some mysterious reason, the Java String type does not come with a reverse method. The canonical way to reverse a Java string str is to first convert it to mutable StringBuilder, reverse its contents, and convert the result back to an immutable string, that is,str = new StringBuilder(str).reverse().toString(); Here's the tester it must pass: @Test public void testPancakeScramble() throws IOException {// Explicit test casesassertEquals("", P2J3.pancakeScramble(""));assertEquals("alu",…C# Write a method that accepts a string as an argument and displaysits contents backward. For instance, if the string argument is"gravity" , the method should display "ytivarg"public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current string
- The countSubstring function will take two strings as parameters and will return an integer that is the count of how many times the substring (the second parameter) appears in the first string without overlapping with itself. This method will be case insensitive. For example: countSubstring(“catwoman loves cats”, “cat”) would return 2 countSubstring(“aaa nice”, “aa”) would return 1 because “aa” only appears once without overlapping itself. public static int countSubstring(String s, String x) { if (s.length() == 0 || x.length() == 0) return 1; if (s.length() == 1 || x.length() == 1){ if (s.substring(0,1).equals(x.substring(0,1))){ s.replaceFirst((x), " "); return 1 + countSubstring(s.substring(1), x); } else { return 0 + countSubstring(s.substring(1), x); } } return countSubstring(s.substring(0,1), x) + countSubstring(s.substring(1), x); } public class Main { public static void main(String[] args) { System.out.println(Recursion.countSubstring("catwoman loves cats","cat"));…C sharp Write a method that accepts a string as an argument and checks it for proper capitalization and punctuation. The method should determine if the string begins with an uppercase letter and ends with a punctuation mark. The method should return true if the string meets the criteria; otherwise, it should return false.Alternate Character DisplayWrite a method that accepts a String object as an argument and then returns the alternate characters as substring starting from index 0. For instance, if the string argument passed is “GREAT”, the method should return “GET”. Demonstrate the method in a program that asks the user to input a string and then passes it to the method.
- Repeating String Write a method that takes a String and an int and return a String that is the original String repeated n times. For example, repeatString("Famous", 3) should return "FamousFamousFamous" The method signature should be public String repeatString(String str, int n) public String repeatString(String str, int n) { //declare a string variable //set up statements for repeating n number of times //create the appropriate return statement }Please help me with this task. Thank you! public class CustomString { String myString; boolean isSet; public CustomString() { this.myString = null; this.isSet = false; } /** * Returns a new string version of the current string where the alphabetical characters specified in the given arg, are removed. * * The alphabetical characters to be removed are case insensitive. * All non-alphabetical characters are unaffected. * If the current string is null, empty, or has not been set to a value, this method should return an empty string. * * Example(s): * - For a current string "my lucky numbers are 6, 8, and 19.", calling remove("ra6") would return "my lucky numbes e 6, 8, nd 19." * - For a current string "my lucky numbers are 6, 8, and 19.", calling remove("6,.") would return "my lucky numbers are 6, 8, and 19." * - For a current string "my lucky numbers are 6, 8, and 19.", calling remove("") would return "my…Pattern and Value are two strings that you must use. The pattern string, which denotes a pattern inside a string, is made up just of the letters a and b. For instance, the string catcatgocatgo matches the pattern aabab (where cat is represented by letter A and go by letter B). Additionally, it matches a, ab, and b pattern. To check whether a value matches a pattern, create a method.