This problem has you write a nested loop to process a list of list of int, and accumulate a list of list of int. The starter codeprovides an accumulator for the result and a loop over the lists, and you need to write the code that checks whether sublist contains onlyeven ints.You'll probably want a one-way flag: a Boolean variable that starts out as True and is set to False if you find an odd int in the sublist. You'llneed to check the value of this variable to figure out whether to append sublist to the even_lists accumulator.1 def only evens (1st: list[list[int]]) -> list[list[int]]:**"Return a list of the lists in 1st that contain only even integers.2.3.>>> only_evens ([[1, 2, 4], [4, e, 6], [22, 4, 3], [2]])4.[[4, e, 6], [2]]8.even_lists = []10for sublist in 1st:11121314return even_listsHistorySubmitP Type here to search100%1:18°C CloudyA 4) ENG10/2

Take the array lists and find the even lists in that array lists. In the given code It will return…

This probiem provides an accumulator for the result and a loop over the lists, and you need to write the code that checks whether sublist contains only even ints. You'll probably want a one-way flag: a Boolean variable that starts out as True and is set to False if you find an odd int in the sublist, You'l need to check the value of this variable to figure out whether to append sublist to the even_lists accumulator. 1 def only evens (1st: list[list[int]]) -> list[list[int]]: **"Return a list of the lists in 1st that contain only even integers. 2. 3. >>> only evens ([[1, 2, 4], [4, 0, 6], [22, 4, 3], [2]]) [[4, e, 6], [2]] 4. 5. 7. 8. even lists = [] 10 for sublist in 1st: 11 12 13 14 return even_lists History Submit

This probiem provides an accumulator for the result and a loop over the lists, and you need to write the code that checks whether sublist contains only even ints. You'll probably want a one-way flag: a Boolean variable that starts out as True and is set to False if you find an odd int in the sublist, You'l need to check the value of this variable to figure out whether to append sublist to the even_lists accumulator. 1 def only evens (1st: list[list[int]]) -> list[list[int]]: **"Return a list of the lists in 1st that contain only even integers. 2. 3. >>> only evens ([[1, 2, 4], [4, 0, 6], [22, 4, 3], [2]]) [[4, e, 6], [2]] 4. 5. 7. 8. even lists = [] 10 for sublist in 1st: 11 12 13 14 return even_lists History Submit

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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This problem has you write a nested loop to process a list of list of int, and accumulate a list of list of int. The starter code provides an accumulator for the result and a loop over the lists, and you need to write the code that checks whether sublist contains only even ints. You'll probably want a one-way flag: a Boolean variable that starts out as True and is set to False if you find an odd int in the sublist. You'll need to check the value of this variable to figure out whether to append sublist to the even_lists accumulator. def only_evens(lst: list[list[int]]) -> list[list[int]]: """Return a list of the lists in lst that contain only even integers. >>> only_evens([[1, 2, 4], [4, 0, 6], [22, 4, 3], [2]]) [[4, 0, 6], [2]] """ even_lists = [] for sublist in lst: # write your code here (please read above for a suggested approach) return even_lists
The for loop iterates across the elements in a given list. So long as there are objects to process, it will keep going. In what way does this statement hold true or false?
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Assume that there is a linked list that connected several names.How do you set up a "while" loop to print the whole list?
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