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This raises the question: Why does the maximum packet lifetime have to be long enough to guarantee that not only the packet, but also its acknowledgements, are gone?

Principles of Information Security (MindTap Course List)

6th Edition

ISBN:9781337102063

Author:Michael E. Whitman, Herbert J. Mattord

Publisher:Michael E. Whitman, Herbert J. Mattord

Chapter6: Security Technology: Access Controls, Firewalls, And Vpns

Section: Chapter Questions

Problem 2RQ

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Concept explainers

Types Of Protocols

A network protocol is a collection of rules that governs the exchange of data between devices connected to the same network. In other words, network protocols are rules that specify how devices communicate or transfer data over a network. The sender and receiver systems must obey the standards to facilitate communication between them.

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This begs the question: why must the maximum packet lifetime be long enough to ensure that not only the packet but also its acknowledgements are lost?
This begs the issue of why the maximum packet lifetime must be long enough to ensure that not only the packet, but also any acknowledgements associated with it, are no longer present.
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Why must the maximum packet lifetime be large enough to assure that not only the packet but also its acknowledgements have vanished?
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Consider there are 4 stations in the token ring. There is only one packet in the ring. Suppose if the station 1 holds the packet until it completes one revolution and returns to it then what could be the Token Holding Time(THT)? 1. THT = Propagation delay+4*bit delay 2. THT= Transmission delay+ Propagation delay +4*bit delay 3. THT = Propagation delay + Transmission delay*4 4. THT = Transmission delay
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Consider there are 4 stations in the token ring. There is only one packet in the ring Suppose if the station 1 holds the packet until it completes one revolution and returns to it then what could be the Token Holding Time (THT)? a) THT = Propagation delay+ 4*bit delay b) THT = Transmission delay + Propagation delay + 4*bit delay c) THT = Propagation delay + Transmission delay *4 d) THT = Transmission delay
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For the sake of this example, let us assume that a packet is being sent from its origin to an address at the other end of the network through a fixed path. The following are other reasons for lateness: How long do the majority of total delays last, and what proportion of total delays are time-dependent?