Asked Dec 19, 2019

Three 9.0- Ω resistors are connected in series with a 12 - V battery.
Find (a) the equivalent resistance of the circuit and (b) the
current in each resistor. (c) Repeat for the case in which all
three resistors are connected in parallel across the battery.


Expert Answer

Step 1


            The resistance in each resistors, R=9.0ohm

            The voltage in the battery, V = 12V

Step 2


The three resistors are connected in series. Therefore, the equivalent resistance becomes


Image Transcriptionclose

R=R;+R,+R; %3D eq = 9.02+9.02+9.02 =27.02

Step 3


Since the resistors are connected in series, the curre...


Image Transcriptionclose

I = R, 12V 270 = 0.44A


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