Three people pull simultaneously on a stubborn donkey. Jack pulls directly ahead of the donkey with a force of 62.3 N, Jill pulls with 71.5 N in a direction 45° to the left, and Jane pulls in a direction 45° to the right with 103 N. (Since the donkey is involved with such uncoordinated people, who can blame it for being stubborn?) Determine the magnitude F of the net force the people exert on the donkey. What is the direction 8 of the net force? Let 0° define straight F = N

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter4: The Laws Of Motion
Section: Chapter Questions
Problem 29P: An object of mass m = 1.00 kg is observed to have an acceleration a with a magnitude of 10.0 m/s2 in...
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Three people pull simultaneously on a stubborn donkey. Jack pulls directly ahead of the donkey with a force of 62.3 N, Jill pulls
with 71.5 N in a direction 45° to the left, and Jane pulls in a direction 45° to the right with 103 N. (Since the donkey is involved
with such uncoordinated people, who can blame it for being stubborn?)
Determine the magnitude F of the net force the people exert
on the donkey.
What is the direction of the net force? Let 0° define straight
ahead, with positive angles to the left and negative angles to
the right. Express as an angle with a magnitude between 0°
and 90°.
F =
0=
N
Transcribed Image Text:Three people pull simultaneously on a stubborn donkey. Jack pulls directly ahead of the donkey with a force of 62.3 N, Jill pulls with 71.5 N in a direction 45° to the left, and Jane pulls in a direction 45° to the right with 103 N. (Since the donkey is involved with such uncoordinated people, who can blame it for being stubborn?) Determine the magnitude F of the net force the people exert on the donkey. What is the direction of the net force? Let 0° define straight ahead, with positive angles to the left and negative angles to the right. Express as an angle with a magnitude between 0° and 90°. F = 0= N
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