Titration Results Initial buret reading (ml) Final buret reading (ml) Total volume used (mL) 0.00 15.00 15.00 HCI Trial 1.10M 0.05 31.10 31.05 NaOH SP 15.00 30.00 15.00 HCI Trial 2 16.05 44.25 28.20 NaOH
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- Data Table 3: Complexometric Titration of Soft Water 5 ml of water 1ml of buffer Hard Water Trial 1 Hard Water Trial 2 Hard Water Trial 3 Initial Syringe Reading (mL) 1ml 1ml 1ml Final Syringe Reading (mL) 77ml 79ml 75ml Volume of EDTA Consumed (mL) .23ml .21ml .25ml Water Hardness ppm CaCO3 (mg/L) Average ppm CaCO3 (mg/L):Data Table 3: Complexometric Titration of Soft Water 6ml of water used (1ml of buffer and 5ml of soft water) Hard Water Trial 1 Hard Water Trial 2 Hard Water Trial 3 Initial Syringe Reading (mL) 1ml 1ml 1ml Final Syringe Reading (mL) 77ml 79ml 75ml Volume of EDTA Consumed (mL) .23ml .21ml .25ml Water Hardness ppm CaCO3 (mg/L) Average ppm CaCO3 (mg/L):Part A: Standardization of a Sodium Hydroxide Solution Titration 1 Titration 2 Titration 3 Mass of 125 mL flask 45.849g 46.715g 44.953g Mass of flask and KHP 46.849g 47.745g 46.003g Initial buret reading (mL) 0.5 ml 0.5 ml 0.5 ml Final buret reading (mL) 27.8 ml 26.5 ml 26.7 ml Volume of NaOH used (mL) 45.11 ml 45.06 ml 45.14 ml Calculations Titration 1 Titration 2 Titration 3 Moles of KHP Moles of NaOH Molarity of NaOH Average Molarity of NaOH: _______________
- Molarity of titrant (NaOH): 0.4550 M HC2H3O2 (aq) + NaOH (aq) → NaC2H3O2 (aq) + H2O (l) Trial # First Second Third Fourth Initial buret reading 0.15 mL 2.43 mL 1.32 mL 0.58 mL Final buret reading 18.62 mL 20.87 mL 20.03 mL 19.14 mL Volume of titrant used 18.47 mL 18.44 mL 18.71 mL 18.56 mL 4) Calculate the molarity of the acetic acid in the vinegar solution (Show your work). use FW for moles-->grams acetic acid. Molarity acetic acid = _____________ M 5) Calculate the weight % of acetic acid in the vinegar. How does this compare with the % listed on the label (5.00%)? (For this calculation assume that density of vinegar is 1.03 g/mL and of course, show your work). Weight % = ___________ 6) If you didn’t get the same weight % of acetic acid as listed on the vinegar label (5.00 %), what are two things (be specific) that could’ve happened during the experiment that could explain the variation from the expected weight %? To do…Data Table 1: Complexometric Titration of Hard Water 6ml of water used (5ml of hard water and 1ml of buffer) Hard Water Trial 1 Hard Water Trial 2 Hard Water Trial 3 Initial Syringe Reading (mL) 1ml 1ml 1ml Final Syringe Reading (mL) 0.55ml .50ml .33ml Volume of EDTA Consumed (mL) 0.45ml .50ml .77ml Water Hardness ppm CaCO3 (mg/L) Average ppm CaCO3 (mg/L): photo shows equation that needs to be used to solveData Table 2: Complexometric Titration of Tap Water photo shows equation to find water hardness 6 ml of water used (5 ml of tap water 1ml of buffer) Hard Water Trial 1 Hard Water Trial 2 Hard Water Trial 3 Initial Syringe Reading (mL) 2ml 2ml 2ml Final Syringe Reading (mL) .61ml .69ml .58ml Volume of EDTA Consumed (mL) 139ml 131ml 142ml Water Hardness ppm CaCO3 (mg/L) Average ppm CaCO3 (mg/L):
- Data Table for Weak Acid Vol. of Titrant pH Avg. Vol. ∆pH/∆vol 0 2.881 0.25 0.622575 0.5 3.193 0.75 0.453769 1 3.420 1.25 0.32668 1.5 3.583 1.75 0.251434 2 3.709 2.25 0.20456 2.5 3.811 2.75 0.173202 3 3.897 3.25 0.150977 3.5 3.973 3.75 0.134517 4 4.040 4.25 0.12191 4.5 4.101 4.75 0.112002 5 4.157 5.25 0.104057 5.5 4.209 5.75 0.097586 6 4.258 6.25 0.092253 6.5 4.304 6.75 0.087819 7 4.348 7.25 0.084111 7.5 4.390 7.75 0.081001 8 4.431 8.25 0.078391 8.5 4.470 8.75 0.076209 9 4.508 9.25 0.074397 9.5 4.545 9.75 0.072912 10 4.582 10.25 0.071719 10.5 4.617 10.75 0.070794 11 4.653 11.25 0.070117 11.5 4.688 11.75 0.069675 12 4.723 12.25 0.06946 12.5 4.757 12.75 0.069467 13 4.792 13.25 0.069696 13.5 4.827 13.75 0.070152 14 4.862 14.25 0.070845 14.5 4.897 14.75 0.071787 15 4.933 15.25 0.072999 15.5 4.970 15.75 0.074507 16 5.007 16.25 0.076346 16.5 5.045 16.75 0.078561 17 5.085 17.25 0.081211 17.5 5.125 17.75 0.084372 18…A 50.00 (±0.02) mL portion of an HCl solution required 29.71(±0.02) mL of 0.01963(±0.0032) M Ba(OH)2 to reach an end point with bromocresol green indicator. ? of HCL = 29.71?? ? 0.01963 ???? ??(??)2 ?? ? 2 ???? ??? ???? ??(??)2/ 50.00?? = 0.02333 ? Calculate the uncertainty of the result (absolute error).Calculate the coefficient of variation for the result.Trial 1: Initial pH= 3.92mL Mass of KHP and Paper= 0.868g Mass of paper= 0.357g Mass of KHP= 0.511g Trial 2: Initial pH= 4.09ml Mass of KHP and Paper= 0.870g Mass of paper= 0.359g Mass of KHP= 0.511g 1)Use Kb, the number of moles of C8H4O4^2- at the equivalence point, and the total volume at that point to calculate the pH for each sample at the equivalence point. Compare these calculated results with the experimental results.
- How will the analyte concentration be altered if the titrant volume recorded is greater than required? cannot be determined from the information given It will be reported lesser than the actual concentration. It will be reported the same as the actual concentration. It will be reported greater than the actual concentration.A standard serum sample containing 102 meq/L chloride was analyzed by coulometric titration with silver ion. Duplicate results of 101 and 98 meq/L were obtained. (a) Calculate the mean error (b) Calculate the relative error (c) Calculate the relative accuracyThe water hardness of tap water has been determined to be 120 (= 120 mg CaCO3 per 1 L of water). After the tap water has run through the ion exchange column, titration of a 20.00 mL sample used only 0.70 mL of 0.0100 M EDTA, to reach the endpoint. Calculate the effectiveness of the ion exchange column: what is the % of the calcium, removed by the ion exchange column? Provide your answer in % and without decimal. ( Please type answer note write by hend)