Write Java code please C.Create an int called zeroCount and assign it the value 0. This will count the number of zeroesin our answer stringd.Create an int called oneCount and assign it the value 0. This will count the number of ones inour answer stringCreate an int called twoCount and assign it the value 0. This will count the number of twos inour answer stringе.f.Create an int called currentNum and assign it the value initialNum4. Print initialNum.5. Create a while loop that terminates when currentNum is equal to 0Within the while loop, create a local int variable called digit and assign to it currentNum 8 37. Use if-else if statements to do the following:6.a. If digit is a 0, increment zeroCountIf digit is a 1, increment oneCountc. If digit is a 2, increment twoCountConcatenate digit to the front of the string answer9. Re-assign currentNum to currentNum / 3b.8.10. After the while loop, use three print statements to output the following on separate lines:a."Decimal representation: [initialNum]"b."Ternary representation: [answer]""[zeroCount] zeroes, [oneCount] ones, and [twoCount]twos"C.11. Create an int variable digitSum and assign it to the sum of the digits in the ternary representationOne way of evaluating this sum is 0* zeroCount +1• oneCount + 2 ° twoCount12. Finally, use a switch statement to print one of the following statements according to the value ofa.digitSum % 5:0: "The ternary digits sum to a multiple of 5!"1: "The ternary digits almost summed to a multiple 5!"4: "So close!"a.b.C.d.Any other value: "Nope!"Example OutputsPlease refer to the PE clarification thread on Ed for examples.HINT: To help debug your code, try inserting print statements in places where variables are changed.Feature RestrictionsThere are a few features and methods in Java that overly simplify the concepts we are trying to teach or break ourauto grader. For that reason, do not use any of the following in your final submission:var (the reserved keyword)System.exitImport RestrictionsYou may not import anything for this homework assignment. Problem DescriptionTypically, we expect the numbers we use to be represented in the decimal numeral system, base-10. However, thisis not the only way we can represent numbers. Computers will often store data in the binary numeral system,base-2. When tallying, people will often use the unary numeral system, base-1. For this assignment, we will beexploring the ternary numeral system, base-3. To represent a decimal number, which we will call n, in ternary, wecan perform the following algorithm:Begin with an empty string to hold our answerCompute n modulo 3 and append it to the front of our answerDivide n by 3 (what kind of division should occur?)Repeat the above two steps until n is zeroTo demonstrate, let's apply the algorithm to n = 100 and see what happens.1. 100 8 3 is 1, so our partial answer is "1"2. 100 / 3 is 333. 33 $ 3 is 0, so our partial answer is "01"4. 33 / 3 is 115.11 % 3 is 2, so our partial answer is "201"6. 11 / 3 is 33 8 3 is 0, so our partial answer is "0201"8. 3 / 3 is 19. 1 3 is 1, so our partial answer is "10201"10. 1 / 3 is 07.11.We reached 0. The final answer is "10201"We can verify that the final answer is correct because1.3 + 0• 3³ + 2•3² + 0 •3' +1·3° = 81 + 0 + 18 + 0 + 1 = 100Notice how this conversion algorithm repeats the same two steps over and over (mod and division). This means wecan implement it with iteration a.k.a. loopstYour assignment will consist of 2 main parts:Start with some arbitrary number in decimal and create the ternary string representationPrint out information about the ternary representationSolution Description1. Create a class called TernaryCreate the main method2.3. Inside, create these variables:a. Create an int called initialNum and assign it any positive integer from 1-1000 (Please refer tothe PE Clarification Thread on Ed for example output.)b. Create a String called answer and assign it to the empty string, "". This will hold our ternaryrepresentation as we build it

Question

Write Java code please C.Create an int called zeroCount and assign it the value 0. This will count the number of zeroesin our answer stringd.Create an int called oneCount and assign it the value 0. This will count the number of ones inour answer stringCreate an int called twoCount and assign it the value 0. This will count the number of twos inour answer stringе.f.Create an int called currentNum and assign it the value initialNum4. Print initialNum.5. Create a while loop that terminates when currentNum is equal to 0Within the while loop, create a local int variable called digit and assign to it currentNum 8 37. Use if-else if statements to do the following:6.a. If digit is a 0, increment zeroCountIf digit is a 1, increment oneCountc. If digit is a 2, increment twoCountConcatenate digit to the front of the string answer9. Re-assign currentNum to currentNum / 3b.8.10. After the while loop, use three print statements to output the following on separate lines:a.&#34;Decimal representation: [initialNum]&#34;b.&#34;Ternary representation: [answer]&#34;&#34;[zeroCount] zeroes, [oneCount] ones, and [twoCount]twos&#34;C.11. Create an int variable digitSum and assign it to the sum of the digits in the ternary representationOne way of evaluating this sum is 0* zeroCount +1• oneCount + 2 ° twoCount12. Finally, use a switch statement to print one of the following statements according to the value ofa.digitSum % 5:0: &#34;The ternary digits sum to a multiple of 5!&#34;1: &#34;The ternary digits almost summed to a multiple 5!&#34;4: &#34;So close!&#34;a.b.C.d.Any other value: &#34;Nope!&#34;Example OutputsPlease refer to the PE clarification thread on Ed for examples.HINT: To help debug your code, try inserting print statements in places where variables are changed.Feature RestrictionsThere are a few features and methods in Java that overly simplify the concepts we are trying to teach or break ourauto grader. For that reason, do not use any of the following in your final submission:var (the reserved keyword)System.exitImport RestrictionsYou may not import anything for this homework assignment. Problem DescriptionTypically, we expect the numbers we use to be represented in the decimal numeral system, base-10. However, thisis not the only way we can represent numbers. Computers will often store data in the binary numeral system,base-2. When tallying, people will often use the unary numeral system, base-1. For this assignment, we will beexploring the ternary numeral system, base-3. To represent a decimal number, which we will call n, in ternary, wecan perform the following algorithm:Begin with an empty string to hold our answerCompute n modulo 3 and append it to the front of our answerDivide n by 3 (what kind of division should occur?)Repeat the above two steps until n is zeroTo demonstrate, let's apply the algorithm to n = 100 and see what happens.1. 100 8 3 is 1, so our partial answer is &#34;1&#34;2. 100 / 3 is 333. 33 $ 3 is 0, so our partial answer is &#34;01&#34;4. 33 / 3 is 115.11 % 3 is 2, so our partial answer is &#34;201&#34;6. 11 / 3 is 33 8 3 is 0, so our partial answer is &#34;0201&#34;8. 3 / 3 is 19. 1 3 is 1, so our partial answer is &#34;10201&#34;10. 1 / 3 is 07.11.We reached 0. The final answer is &#34;10201&#34;We can verify that the final answer is correct because1.3 + 0• 3³ + 2•3² + 0 •3' +1·3° = 81 + 0 + 18 + 0 + 1 = 100Notice how this conversion algorithm repeats the same two steps over and over (mod and division). This means wecan implement it with iteration a.k.a. loopstYour assignment will consist of 2 main parts:Start with some arbitrary number in decimal and create the ternary string representationPrint out information about the ternary representationSolution Description1. Create a class called TernaryCreate the main method2.3. Inside, create these variables:a. Create an int called initialNum and assign it any positive integer from 1-1000 (Please refer tothe PE Clarification Thread on Ed for example output.)b. Create a String called answer and assign it to the empty string, &#34;&#34;. This will hold our ternaryrepresentation as we build it

Accepted Answer

% operator gives the remainder and
/ operator gives the quotient.