To determine the organic material in a dried lake bed, the percent carbon by mass is measured at two different locations. To compare the means of the two different locations, it must first be determined whether the standard deviations of the two locations are different. Location 1 standard deviation: 0.050 Location 2 standard deviation: 0.34 What is the calculated ? value for comparing the standard deviations?
To determine the organic material in a dried lake bed, the percent carbon by mass is measured at two different locations. To compare the means of the two different locations, it must first be determined whether the standard deviations of the two locations are different. Location 1 standard deviation: 0.050 Location 2 standard deviation: 0.34 What is the calculated ? value for comparing the standard deviations?
Chapter32: Gas Chromatography
Section: Chapter Questions
Problem 32.14QAP
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Question
To determine the organic material in a dried lake bed, the percent carbon by mass is measured at two different locations. To compare the means of the two different locations, it must first be determined whether the standard deviations of the two locations are different.
Location 1 standard deviation: 0.050
Location 2 standard deviation: 0.34
What is the calculated ? value for comparing the standard deviations?
Transcribed Image Text:Sample
1
2
3
نیا
4
5
Location 1 (% Location 2 (%
C)
C)
60.40
60.10
60.30
60.90
60.30
60.30
60.40
60.80
60.30
60.40
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