• To find sn, we raise $₁ to the power Sn ||*)/2-1/ 1/n 2-1/2) 2(n+1)/2 |sn|1/n Sn = 1/2 n

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.8: Probability
Problem 18E
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Is this step here correct? How does it become 2^(-1/2) here?

• To find s₂, we raises to the power n
|Sn|1/n :
1
2(n+1)/2
1/n 2-1/2
=
=
1
√/2
Transcribed Image Text:• To find s₂, we raises to the power n |Sn|1/n : 1 2(n+1)/2 1/n 2-1/2 = = 1 √/2
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