To test Hg: u= 103 versus H,: u# 103 a simple random sample of size n= 35 is obtained. Complete parts a through e below. E Click here to view the t-Distribution Area in Right Tail. (a) Does the population have to be normally distributed to test this hypothesis? Why? O A. Yes, because n2 30. O B. No, because n2 30. OC. Yes, because the sample is random. O D. No, because the test is two-tailed. (b) If x = 99.9 ands= 5.7, compute the test statistic. The test statistic is to = (Round to two decimal places needed.) (c) Draw a t-distribution with the area that represents the P-value shaded. Choose the correct graph below. O A. OB. OC. (d) Approximate the P-value. Choose the correct answer below. O A. 0.005 < P.value < 0.01 O B. 0.002 < P.value < 0.005 OC. 0.01

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter13: Probability And Calculus
Section13.3: Special Probability Density Functions
Problem 53E
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To test H,: µ= 103 versus H1: µ# 103 a simple random sample of size n= 35 is obtained. Complete parts a through e below.
E Click here to view the t-Distribution Area in Right Tail.
(a) Does the population have to be normally distributed to test this hypothesis? Why?
O A. Yes, because n2 30.
O B. No, because n2 30.
OC. Yes, because the sample is random.
O D. No, because the test is two-tailed.
(b) If x = 99.9 and s = 5.7, compute the test statistic.
The test statistic is to =. (Round to two decimal places as needed.)
(c) Draw a t-distribution with the area that represents the P-value shaded. Choose the correct graph below.
OA.
OB.
OC.
(d) Approximate the P-value. Choose the correct answer below.
O A. 0.005 < P-value < 0.01
O B. 0.002 <P-value < 0.005
O C. 0.01 < P-value <0.02
O D. 0.001 <P-value < 0.002
Interpret the P-value. Choose the correct answer below.
O A. If 1000 random samples of size n= 35 are obtained, about 3 samples are expected to result in a mean as extreme or more extreme than the one observed if u = 103.
O B. If 1000 random samples of size n= 35 are obtained, about 10 samples are expected to result in a mean as extreme or more extreme than the one observed if p = 103.
Transcribed Image Text:To test H,: µ= 103 versus H1: µ# 103 a simple random sample of size n= 35 is obtained. Complete parts a through e below. E Click here to view the t-Distribution Area in Right Tail. (a) Does the population have to be normally distributed to test this hypothesis? Why? O A. Yes, because n2 30. O B. No, because n2 30. OC. Yes, because the sample is random. O D. No, because the test is two-tailed. (b) If x = 99.9 and s = 5.7, compute the test statistic. The test statistic is to =. (Round to two decimal places as needed.) (c) Draw a t-distribution with the area that represents the P-value shaded. Choose the correct graph below. OA. OB. OC. (d) Approximate the P-value. Choose the correct answer below. O A. 0.005 < P-value < 0.01 O B. 0.002 <P-value < 0.005 O C. 0.01 < P-value <0.02 O D. 0.001 <P-value < 0.002 Interpret the P-value. Choose the correct answer below. O A. If 1000 random samples of size n= 35 are obtained, about 3 samples are expected to result in a mean as extreme or more extreme than the one observed if u = 103. O B. If 1000 random samples of size n= 35 are obtained, about 10 samples are expected to result in a mean as extreme or more extreme than the one observed if p = 103.
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