to correct the power factor to reduce
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A plant has a load of 290 kilowatt with an average power factor of 70%. The owner requests you to correct the power factor to reduce its power consumption. How much capacitor kVAR is required to increase the power factor to 95%?
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- You are an electrician working in an industrial plant. A 30-hp three-phase induction motor has a current draw of 36 amperes at full load. The motor is connected to a 480-volt line. A three-phase wattmeter indicates a true power of 22 kW. Determine the power factor of the motor and the amount of capacitance needed to correct the power factor to 95. Also determine the minimum voltage rating of the capacitors. The capacitors are to be connected in wye.The power factor of a certain load is improved to 0.92 lagging with the addition of a 30 kVAR bank of capacitors. If the resulting supply apparent power is 200 kVA, determine the power factor before correction.A 96 kVA load operates at 0.79 lagging power factor when connected to a 230 V, 60Hz AC source. The power factor is to be improved to 0.93 lagging. The power factor is to be corrected by a capacitor bank. However, the capacitors are loosely connected and take 34 kW when connected to a 230V, 60Hz AC source. What is the kVAR rating of the capacitor bank?
- The load of an industrial plant consists of 600kVA at a power factor of 0.75 lag. One large motor is to be added to the load and will require 150kW Determine the new load (in kVA) if the motor installed is an induction motor operating at a power factor of 0.85 lagging.The average load of a dairy plant at 11 kV, 50 Hz is 950 kW at 80 percent power factor but the maximum contract load of plant is 1200 kW. As per local electricity regulating authorities norms, consumer must keep the power factor of 95 percent to avoid any poor power factor penalty. Determine the following (i) Rating of capacitor bank (in kVAr) (ii) The capacitance of the capacitor bank (in micro Farad) (iii) Explain why the power factor becomes low and how the capacitor bank will assists to improve the power factor?A load of 300KW with power factor 0.65 lagging has the power factore improved to 0.90 lagging by parallel capacitors. How many Kvar must these capacitors furnish and what is the resulting percent reduction in apparent power
- A load of 300 kW with a power factor of 0.65 lagging has the power factor improved to 0.9 lagging by the addition of parallel capacitors. What kvar of capacitors does this require and what percent reduction in kVA results?A 240-V rms 60-Hz supply serves a load that is 10 kW (resistive), 15 kVAR (capacitive), and 22 kVAR (inductive). What is the current drawn from the supply in amperes? And what is the required capacitor rating in microfarads required to improve the power factor to 0.96 ?If the apparent power of a source is known, then the power factor, active and reactive powers can be calculated from it. Select one: True False
- A transformer connected to a120 V (rms) ac line is to supply 12.0 V (rms) to a portable electronic device.The load resistance in the secondary is 5.00 Ω. What rms current must the secondary supply?7. An alternator is generating power motor absorbing 60 kW is connected in parallel with a factory load of 240 kW having a lagging power factor of 0.8 the combined load has a pf of 0.9 Determine the kVAR supplied by the motor.A 100 kVA, 230V load operates at 0.80 lagging power factor. The power factor is to be improved to 0.80 leading by a capacitor bank. However, the capacitors are loosely connected and take 50 kW when connected to a 230V, 60Hz AC source.a. What is the total KVA consumption when the capacitor bank is connected? (162.5 kVA)b. What is the kVAR rating of the capacitor bank? (157.5 kVAR)c. Find the capacitance of the capacitor. (7.8976 mF)