WHY (-NC IC ) & AND SUM THENUMBER OF TURNS ANDCURRENTFOR A AND Bair-gapLieloo emIbIaA=2cm +2cmMr = 1400Lg=5mmF=ØRIcNa = 335, Nb=600F=Nala + Nb Ib- Nc IcNc=600Ia=1.6A, Ibu AF=335*1.6 +600 *U-600*3=1136 AtI<=3 A$9LiRi=MARi=(oux10²UTTX107*100*4x154-UNbN₂Ri=1421747043Rg=Lg5x103410741*4*104MART-RI+ Rg=11373976-34~209-1136FR-11373976-34Na1446Rg99 52229-299~2-=9.98 x105 wb

To explain why NaIa and NbIb are taken positive whereas NcIc is written with negative sign ?

WHY (-NC IC) AND SUM THE NUMBER OF TURNS AND CURRENT FOR A AND B air-gap Lieloc em Ia A=2cm +2cm Mr = 1400 Lg=5mm F=ØR Ic" Na = 335, Nb=600 F₂NaIa + Nb Ib - Nc Ic Nc=600 Ia=1.6A₂ Ib=U A F-335*1.6 +600 *U-600*3=1136 At I<=3 A $9 Ri Li MA -2 (oux10² UTT X 167 * 100 *UX 15" - Ri= 1421747.043 Rg= 5x10³ = MA 4714104 RT=Ri+ Rg=11373976.34-2 09- F 1136 - Þ Ri= = وا (1₂ Na 1446 Nb N₂ I Rg -=9952229-299~2 -=9.98 x 155 wh

WHY (-NC IC) AND SUM THE NUMBER OF TURNS AND CURRENT FOR A AND B air-gap Lieloc em Ia A=2cm +2cm Mr = 1400 Lg=5mm F=ØR Ic" Na = 335, Nb=600 F₂NaIa + Nb Ib - Nc Ic Nc=600 Ia=1.6A₂ Ib=U A F-3351.6 +600 U-6003=1136 At I<=3 A $9 Ri Li MA -2 (oux10² UTT X 167 100 *UX 15" - Ri= 1421747.043 Rg= 5x10³ = MA 4714104 RT=Ri+ Rg=11373976.34-2 09- F 1136 - Þ Ri= = وا (1₂ Na 1446 Nb N₂ I Rg -=9952229-299~2 -=9.98 x 155 wh

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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