Topic: BinaryFill in the boxesWill give you high rating thank you!! AddrAddr (Bin)Contents10 10 110 0 0 1O 000 0 0 o00 0 0 11 1 1 00 1 1 1 1 1 1 10 0 0 0 1 0 0 110 0 0 0 1 0 0 1 1 1 010 10 100 0 1 0 0 100 1 100 0 1 1 1 0 0 000 0000 000010 0100 0000 000111100 0000 00100 1 0 0 0 0 00 02300 0000 00111 0 0 01...1 1 0 0 1 10 0 1 0102111 1111 110110221 00 1111 1111 111011102311 1111 111111Address space from 0 to 2"-1 where n is the number of address bitsCan store 1024 words. Because each word is 2 bytes, can store 2048 bytes or 2kBThe address of the first word is 0, the second word is 1, the third word is 2, and the last word is 1023.Now, try to fill in the blanks for a word-addressable machine with 4 address lines, but the word size is 64 bits instead:• the memory size iswords, orbytes• the address of the first word is• the address of the second word is• the address of last word is1,

Here word size=64bit = 64/8=8 Bytes.

The address of the first word is 0, the second word is 1, the third word is 2, and the last word is 1023. Now, try to fill in the blanks for a word-addressable machine with 4 address lines, but the word size is 64 bits ins • the memory size is words, or bytes • the address of the first word is

The address of the first word is 0, the second word is 1, the third word is 2, and the last word is 1023. Now, try to fill in the blanks for a word-addressable machine with 4 address lines, but the word size is 64 bits ins • the memory size is words, or bytes • the address of the first word is

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Related questions

Q: sider a "little-endian" byte-addressable computer which has the a 0x01 at address 0, 0x23 at address…

A: Little endian format means least significant bits are stored first. Address 0:0x01 Address 1:0x23…

Q: 3- address line are necessary to address two megabytes (2048k) of memory? 4- bits are stored by a…

A: Microprocessors use address lines to correspond to a certain memory.

Q: How much better is segmented memory address translation than a straight translation?

A: Segmentation Partition speeds up PC information recovery by giving information connected with the…

Q: suppose, a soft real-time system has 100 m bytes of program memory that is loaded at 75% 16M bytes…

A: Given Total memory=100 Used memory=16 +10 = 26 Formula to calculate Total memory utilisation=…

Q: Suppose the memory of a computer contains the following hex values: Address Ox100 Address Ox101…

A: Actually the answer has given below:

Q: Q.In a computer instruction format, the instruction length is 11 bits and the size of an address…

A: 45 one-address instructions: 45 one-address instruction consists of an opcode with one address…

Q: The physical addresses will change from hop to hop, but the logical addresses usually remain the…

A: Answer in next step

Q: Suppose that 50% of a program requires serial execution. With a computer equipped with a quad-core…

A: A ton of elements can change the response here. Situation 1 :- Assuming that 1 center is saved…

Q: Can a specific physical address have more than two logical addresses? Give your opinion with…

A: Answer is given below .

Q: Logical address 2000:2000 equal: 22000H in physical address Select one: True False

A: Given: We have to discuss logical address 2000:2000 equal : 22000H in physical address.

Q: Suppose the memory cells at address A4 to B3 in the machine described in langua table contains the…

A: Machine Cycle PC Increment of PC IR Register that has value changed Comment on Output…

Q: Logical Address=33bit and Physical Address=24bit Page Size =2KB. System is byte addressable. Find…

A: In this question, the logical address, the physical address, and the page size is given. It is also…

Q: If 20 bits are requires to address 1MB address space, then how many bits are required to address 2…

A: 1 MB= 1000 KB 1 KB= 1000 Bytes 1 Byte =8 Bits

Q: For the 8086 memory segment (011A) h with an offset (2B35) h, the memory address is

A: Need to calculate the memory address of Memory Segment(011A)h with offset (2B35)h Memory Segment :…

Q: How many address bit a processor need to access 64 TB?

A: I have provided an answer to this question in step2.

Q: A computer system has a word addressable memory. Each word is 16 bits. If the address bus of this…

A: Option 1) In general memory is divided into cells.For example 16K×8 memory means it has 16K cells…

Q: How many address lines are required to address 8K bytes of memory? Write only the number

A: Address space defines a range of discrete addresses, each of which may correspond to a network host,…

Q: Suppose a CPU has 4 data pins. How many operations will it take to read a 32-bit word? Please show…

A: Dear Student, Each pin on a cpu can take input or provide output of 1bit of data in each clock…

Q: Q3. Mark True or False, correct when false: a) Address bus is bidirectional b) Data bus is…

A: NOTE: As per our guidelines we are supposed to answer only one question. Kindly repost other…

Q: Do not copy from other websites Correct and detailed answer will be Upvoted else downvoted. Thank…

A: Here I am trying to provide you the correct solution It is given address space is 32768.

Q: What distinguishes a 7CH bit address from a 7CH byte address? Where in memory does bit address 7CH…

A: Difference between 7CH bit address and byte address.

Q: Q6. Answer True or False for the followings: a) Machine code is the assembly code b) Data field is…

A: machine code is the assembly code data field is 16 bit while address field is 8 bit Trainer kit can…

Q: A digital computer has a memory unit with 24 bits per word. The instruction set consists of 150…

A: Introduction: An instruction format defines the different component of an instruction. The main…

Q: For a system that uses 8-KB page size, calculate the page number and offset for the "6070281"…

A: Paging is a memory management strategy that does away with the need for contiguous physical memory…

Q: Compute the address space of the memory with 15 address bits/lines. a. 32,767 O b. 32,768 O c.…

A: In the question address bits are given which represent how much address space it will represent. If…

Q: a) What is the physical address given : Segment – 4042H Offset – 0580H b) How many Flag Register in…

A: a) Segment - 4042H A segmented memory is a way of addressing computer memory, which can be physical…

Q: The size of the memory could be given as: Size of the memory =Number of Words× Number of bits per…

A: Given:

Q: Endianness Assume that a snippet of memory is shown below (in hex), starting with the byte at…

A: Dear Student, In big-endian machine the data is stored in the same order ie the byte which is first…

Q: Suppose that a system uses 32-bit memory words and its memory is built from 16 1M × 8 RAM chips. How…

A: Given, 32-bit memory word 16 1M × 8 RAM chips

Q: The table below shows a segment of primary memory from a Von Neumann model computer Address Data…

A: It is defined as a reference to a specific memory location used at various levels by software and…

Q: Question 13 Suppose the memory of a computer is as follows (assume all numbers are represented in…

A: Here, we are given a memory of a computer which contains four hexadecimal values and we are asked…

Q: What is the highest address in MIPS memory architecture referring to a word in hex? The lowest…

A: H . in MIPS 32bit the address can go from 0x0 to 0xffff i.e. 232 - 1 in MIPS 64 bit the address…

Q: For a system that uses 10-KB page size, calculate the page number and offset for the "200001"…

A: The formula for calculating Page number = (address reference / page size) This is the page number…

Q: Consider a system with a cell size of 128 bits that needs to be able to address 103 MB of memory.…

A: Data Given:- Cell size = 128 bits Memory size = 103 MB Data to be finded out:- Number of address…

Q: The memory units that follow are specified by the number of words times the number of bits per word.…

A: Explanation: An address line indicates the physical storage directly to access and store data. A…

Q: A main memory in a computer uses pages of 1024 bytes and has a page table of 64 entries. What is the…

A: Task :- choose the correct option for given question.

Q: 2. Memory contents (in hexadecima 1000, 7800, F400 for addresses 80.

A: Please let me know if you need anything else in this, note that it said next T0 instruction means…

Q: in a certain microcomputer system, the microprocessor is connected to an external memory of size…

A: In a certain microcomputer system, the microprocessor is connected to an external memory of size…

Q: How many address lines and input-output data lines are needed in 32K x 2 memory? Give the number of…

A: Given data is: 32K x 2 1K=1024 bits 32K= 32768 bits So 32768 bits can be represented as the 215…

Q: How many address bits are needed to reach 1024K words of memory?

A: Number word present in a memory = 1024K word…

Q: Part 1 A small computer on a smart card has four page frames. At the first clock tick, the R bits…

A: Since you have asked multiple questions, according to the company's policy we will solve the first…

Q: The following addresses of a Little-Endian machine contain the given hex values shown. If a 32-bit…

A: ANS: In little Indian notation : Lower address contain lower bit and higher address contain higher…

Q: A computer system interfaces a memory with a 32-bit address bus and a 16-bit data bus. The memory…

A: Given: A computer system interfaces a memory with a 32-bit address bus and a 16-bit data bus. The…

Q: For a 512k x 32 memory system, what is the data width at each address location? 19 32 512k 16M

A: Given, Size of memory system = 512k x 32 For a m x n memory system, Size of address = log 2 m Size…

Q: If a string is stored at the memory address 0x20008000 and the string is “Cortex-M”, show the memory…

A: Actually, string is a sequence of characters.

Q: Suppose a system has a byte-addressable memory size of 256MB. How many bits are required for each…

A: Suppose a system has a byte-addressable memory size of 256MB. How many bits are required for each…

Q: Assume a 24-bit MAR that is organized as follows: row select lines 12 bits column select lines 12…

A: Size and Dimension of 24 nit MAR is given The Maximum size of memory on 24 bit machine is 2^24…

Q: A new PIC18 has been developed with a program memory of 32 MB. What should be the length (number of…

A: Option D

Q: The table below shows a segment of primary memory from a Von Neumann model computer Address Data…

A: This is The flow of instruction execution MAR<-- PC MBR<--Memory[MAR] PC=PC+1 IR<-- MBR

Concept explainers

Computer Fundamentals

The computer is termed computation. For calculating or computing something the device that has been used is known as the computer. Or we can say that for performing a fast arithmetic operation the device that has been used is a computer. Storing, processing, and retrieving are the main features of a computer. 

Question

Topic: Binary

Fill in the boxes

Will give you high rating thank you!!

Addr
Addr (Bin)
Contents
10 10 1
10 0 0 1
O 000 0 0 o00 0 0 1
1 1 1 0
0 1 1 1 1 1 1 10 0 0 0 1 0 0 1
10 0 0 0 1 0 0 1 1 1 0
10 10 10
0 0 1 0 0 10
0 1 100 0 1 1 1 0 0 0
00 0000 0000
1
0 0
1
00 0000 0001
1
1
1
00 0000 0010
0 1 0 0 0 0 0
0 0
2
3
00 0000 0011
1 0 0 0
1
...
1 1 0 0 1 10 0 1 0
1021
11 1111 1101
1022
1 00 1
1
11 1111 1110
1
1
1023
11 1111 1111
1
1
Address space from 0 to 2"-1 where n is the number of address bits
Can store 1024 words. Because each word is 2 bytes, can store 2048 bytes or 2kB
The address of the first word is 0, the second word is 1, the third word is 2, and the last word is 1023.
Now, try to fill in the blanks for a word-addressable machine with 4 address lines, but the word size is 64 bits instead:
• the memory size is
words, or
bytes
• the address of the first word is
• the address of the second word is
• the address of last word is
1,

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, computer-science and related others by exploring similar questions and additional content below.

Similar questions

Data block to be decoded: 00 11 bc b5 49 40 b8 8d 12 00 0d fa 08 00 45 00 00 37 99 09 00 00 ff 11 ea 9f 0a 07 03 1a 42 aa e8 41 c7 19 00 35 00 23 a3 9e 02 90 01 00 00 01 00 00 00 00 00 00 05 6d 69 74 72 65 03 6f 72 67 00 00 01 00 01 Please answer the following questions after decoded the above data block: Q1: (Layer 4) Protocol is: Q2: Source MAC address: Q3: Destination MAC address: Q4: Source IP address: Q5: Destination IP address: Q6: Source (Layer 4) Port #: Q7: Destination (Layer 4) Port # : Q8: (Application Layer) Payload description and contents.
Data block to be decoded: 00 11 bc b5 49 40 b8 8d 12 00 0d fa 08 00 45 00 00 37 99 09 00 00 ff 11 ea 9f 0a 07 03 1a 42 aa e8 41 c7 19 00 35 00 23 a3 9e 02 90 01 00 00 01 00 00 00 00 00 00 05 6d 69 74 72 65 03 6f 72 67 00 00 01 00 01 Please answer the following questions after decoded the above data block: Q1: (Layer 4) Protocol is: Q2: Source MAC address: Q3: Destination MAC address: Q4: Source IP address: Q5: Destination IP address: Q6: Source (Layer 4) Port #: Q7: Destination (Layer 4) Port # : Q8: (Application Layer) Payload description and contents. Please I left out questions-6,7and 8
Data file: 736.2 731.6 829.8 875.8 568.3 292.2 231.1 868.9 66.7 811.9 292.0 967.6 419.3 578.1 322.5 471.7 980.0 378.8 784.1 116.8 900.4 355.3 645.7 603.6 409.1 652.1 144.1 590.6 953.1 954.0 502.0 689.3 685.6 331.9 565.1 253.9 624.1 796.2 122.8 690.7 608.0 414.8 658.3 27.3 992.9 980.8 499.0 972.8 359.7 283.1 89.7 260.1 638.4 735.4 863.6 47.5 387.5 7.7 638.1 340.6 961.7 140.1 29.8 647.3 471.9 594.9 901.2 96.0 391.1 24.0 786.7 999.1 438.7 445.0 26.4 431.6 425.9 525.4 404.4 785.6 808.5 494.1 45.7 447.0 229.5 909.3 494.4 617.0 917.0 132.5 957.5 878.8 272.6 987.4 526.1 744.5 582.3 427.3 840.5 973.3
+1Loop code00
95. The SQL statement SELECT SUBSTR(‘123456789’, INSTR(‘abcabcabc’,’b’), 4) FROM EMP; prints a. 6789 b. 2345 c. 1234 d. 456789
Need answer for this. Theres a txt file of data given. Below : Txt file name is A2data6.txt 6 6 3 2 74 11 27 14 712 3 1814 8 217 18 1619 3 1520 17 1024 12 727 16 831 1 734 13 937 6 738 5 1042 1 242 7 1046 9 147 8 1052 18 1654 8 058 6 1658 1 2062 8 2066 12 166 8 1269 13 1473 16 175 19 1880 5 682 6 785 15 585 10 385 11 1690 17 194 6 695 4 1296 14 799 6 3101 1 4103 19 7105 17 19109 14 13111 19 15115 17 8116 13 13119 14 8123 5 19125 7 10128 1 7129 11 19132 11 1133 14 0134 16 18139 17 1141 4 0142 19 5144 17 17146 3 10147 12 5150 11 10155 8 18156 0 18159 3 14164 18 2168 5 3171 6 10174 5…
The intuitive method for converting fractional values from base 2 to base 10 can be applied when computing fractional values from base 3 to base 10. Hence 0.12201 base 3 may be computed by which expression? a. (1 X 1/3) + (2 X 1/9) + (2 X 1/27) + (1 X 1/81) b. (1 X 1/3) + (2 X 1/9) + (2 X 1/27) + (1 X 1/243) c. (1 X 1/2) + (2 X 1/4) + (2 X 1/8) + (1 X 1/16) d. (1 X 1/2) + (2 X 1/4) + (2 X 1/8) + ( 1 X 1/32)
Find the check digits for the following ISBN-13s: 978 0 385 50422 __ 978 8 422 69156 __
calculate the unit roots of those data using R studio. Corn Soybeans 107.3439992 212.1854389 119.9418335 223.3474526 109.0499573 224.0288101 100.7826335 216.8401058 106.9503123 210.3174476 107.0264359 211.8026538 108.2339452 207.8063774 107.6806234 205.1881272 113.3974024 211.9710793 109.4783249 218.68513 99.38355509 204.6216053 94.59194946 203.9325921 95.29482524 212.1624718 97.47875214 220.3617288 101.0777537 247.1796532 114.3085302 240.8483875 123.4909185 251.9414999 112.0336965 247.5318155 97.49782817 215.0716386 98.09031677 203.4962171 107.8345006 205.1651601 113.8585027 213.1883359 128.0398865 226.1417838 144.0723724 251.5663705 164.1147054 268.049097 196.5570933 290.1817318 176.5597483 294.185664 120.8602168 257.4153269 122.7673162 284.8380517 118.6350199 312.6588731 110.2028834 267.9878514 117.0844472 256.9253619 113.9421438 244.5154688 104.8021596 234.1190254 91.6590449 209.3375178 96.06801605…
Use Python Code Covid-19 deaths table Country/Region Lat Long 4/1/2020 4/2/2020 4/3/2020 4/4/2020 4/5/2020 4/6/2020 4/7/2020 4/8/2020 4/9/2020 Afghanistan 33 65 4 4 5 6 8 11 14 17 19 Albania 41.1533 20.1683 5 13 23 34 56 104 178 240 315 Algeria 28.0339 1.6596 1 1 2 4 5 8 15 26 56 Andorra 42.5063 1.5218 23 34 56 78 103 204 336 504 709 Angola -11.2027 17.8739 7 12 23 53 89 142 203 310 420 Antigua and Barbuda 17.0608 -61.7964 0 0 1 1 1 2 3 5 8 Argentina -38.4161 -63.6167 58 103 205 359 498 630 1004 1597 2102 Armenia 40.0691 45.0382 23 29 38 57 89 108 204 307 405 your task is :Make a visualization alignment of growth curves across countries with the number of COVID-19 deaths >=25
A botanist is doing fieldwork assigns an eight-character alphanumeric code to each sample collected. The first character must be 6, 7, or 8; the next three characters can be any capital letter, A through Z; the fifth character could be any digit except for 0; and the rest of the characters can be any capital letter, B through K. Digits and letters can be repeated. Determine how many possible ID numbers there are using the fundamental counting principle, and explain each step. Show work for all steps Thanks
What is Big-endian order of 78563412h? (first column represents the address) a) 0003 78 0002 56 0001 34 0000 12 b) 0003 56 0002 78 0001 12 0000 34 c) 0003 12 0002 34 0001 56 0000 78 d) 0003 34 0002 12 0001 78 0000 56