Question 13 Suppose the memory of a computer is as follows (assume all numbers are represented in hexadecimal notation)- Address 0x100 12 Address 0x101 34 Address 0x102 56 Address 0x103 78 What integer value is this on a little-endian computer? Express in hexadecimal notation.
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- The following data segment starts at memory address 1000h (hexadecimal) .data printString BYTE "ASSEMBLY IS FUN",0 moreBytes BYTE 25(DUP)0 dateIssued DWORD ? dueDate DWORD ? elapsedTime Word ? What is the hexadecimal address of dueDate ? a. 1045h b. 1029h c.1010h d. 102DhCan u explain this code in detail. I will Upvote : #include<stdio.h> #include<stdlib.h> #include<time.h> struct MainMem { int start_add; int pn; }; int main() { int s,i,totPages,pno,offset,n,r,arr[200]={0},phy_add,fno[100]; struct MainMem mm[100]; srand((unsigned)time(NULL)); printf("Logical Address To Physical Address\n"); printf("Enter the Size of File : "); scanf("%d",&n); printf("Enter the Page Size : "); scanf("%d",&s); totPages=n/s; for(i=0;i<totPages;i++) { r=rand()%totPages; if(arr[r] == 1) { i--; continue; } arr[r]=1; mm[i].pn=r; mm[i].start_add=i*s; fno[r]=i; } printf("\n*************\n"); printf("The Structure of Main Memory\n"); printf("***********\n"); printf("Frame\tPage\nNumber\tNumber\n------\t------\n"); for(i=0; i < totPages; i++) { printf("%d\t%d\n",i,mm[i].pn); } printf("***********\n"); printf("Enter The Logical Address\nPage Number : "); scanf("%d",&pno); printf("Offset : "); scanf("%d",&offset); if(pno >= totPages…A.) What are the contents in hex of the memory location at the following address in binary: 0000 1100 0000 1111? (Enter hex like the following example: 0x2A3F) In all computer models, the contents of a memory location can be interpreted as data. B.) Interpret the contents at address 0xFFFF as a two's complement integer in base 10. C.) Interpret the contents at address 0x0C0C as two ASCII characters. D.) Interpret the contents at the same address as C.) above as an unsigned integer in base 10.
- Consider the following image that represents part of the memory of a 16-bit address space that has an addressability of 2 bytes (like LC-3): A memory location can store an address. We call that memory location's contents a "pointer" since it's an address that "points" to another memory location. G.) Interpret the contents at address 0x0C0B as a pointer. (Enter hex like the following example: 0x2A3F) H.) What are the contents of the memory location that the pointer above is pointing to? (Enter hex like the following example: 0x2A3F) Another reference : LC-3 Opcodes in Hex ADD 0x1 JMP 0xC LDR 0x65.How many bytes in the memory will be occupied by short int array[10] 10 Bytes 20 Bytes 40 Bytes 60 Bytes 6.Given the definition void myFunc(int a, int* b , int* c)which statement is true The values of the aliases a, band c are available to the function Only the addresses of the variables b, care available to the function myFunccannot change the variable whose value is copied to a myFunc can change the value of the variable whose address is copied into b all of the aboveQuestion Show how the following values would be stored bybyte-addressable machines with 32- bit words, using little endianand then big endian format. Assume each value starts at address301816. Draw a diagram of memory for each, placing the appropriatevalues in the correct (and labeled) memory locations. a. 56789ABC16 b. 2014111910 The memory unit of a computer has256K words of 32 bits each. The computer has an instruction formatwith 4 fields: an opcode field; a mode field to specify 1 of 7addressing modes; a register address field to specify one of 16registers; and a memory address field. Assume an instruction is 32bits long. Answer the following: a. How large must the mode field be? b. How large must the register field be? c. How large must theaddress field be? d. How large is the opcode field? 4. In a computerinstruction format, the instruction length is 12 bits and the sizeof an address field is 4 bits. Is it possible to have: 13 2-address instructions 45 1-address instructions…
- Suppose a computer system uses 16-bit addresses for both its virtual and physical addresses. In addition, assume each page (and frame) has size 256 bytes. a) Suppose that the OS uses a two-level page table. Draw the page table. (Assume that frames 7 through 221 are free, so you can allocate space for the page table there.) In addition, suppose that the page-table directory storage comprises a whole number of consecutive full frames. (For examples: if the directory entry is 2 bytes, the entry’s storage comprises 1 frame; if the directory entry is 260 bytes, the entry’s storage comprises 2 consecutive frames.) b) What is the size of the two-level page table c) Now, translate the virtual addresses shown in question I(e) to physical addresses for the two-level page table. Show how you obtain your answers. 0x0389 0xDF78 0x0245 0x8012By assuming that X is the last digit of your student number and 3X is a two digitnumber, consider memory storage of a 64-bit word stored at memory word 3X ina byte-addressable memory(a) What is the byte address of memory word 3X?(b) What are the byte addresses that memory word 3X spans?(c) Draw the number 0xF1234567890ABCDE stored at word 3X in both big-endianand little-endian machines. Clearly label the byte address corresponding to eachdata byte value.Assume a computer that has 32-bit integers. Use a table to clearly show how each of the following values would be stored sequentially in memory, starting at address 0x100, assuming each address holds one byte. 0x123456BA 0xabcde -28 (decimal values, assume the machine uses 2's complement notation. 0xFEDC
- ) Consider the following sequence of virtual memory references (in decimal) generatedby a single program in a pure paging system:100, 110, 1400, 1700, 703, 3090, 1850, 2405, 2460, 4304, 4580, 3640a. Derive the corresponding reference string of pages (i.e. the pages the virtual addressesare located on), assuming a page size of 1024 bytes. (Assume that page numberingstarts at 0)b. For the page sequence derived above, determine the number of page faults for each ofthe following page replacement strategies, assuming that two (2) page frames areavailable to the program.i. LRUii. FIFOiii. OPT (Optimal)Suppose a computer system uses 16-bit addresses for both its virtual and physical addresses. In addition, assume each page (and frame) has size 256 bytes. Could you hand draw the page table, if possible a) Suppose that the OS uses a two-level page table. Draw the page table. (Assume that frames 7 through 221 are free, so you can allocate space for the page table there.) In addition, suppose that the page-table directory storage comprises a whole number of consecutive full frames. (For examples: if the directory entry is 2 bytes, the entry’s storage comprises 1 frame; if the directory entry is 260 bytes, the entry’s storage comprises 2 consecutive frames.) b) What is the size of the two-level page tablehi can u anwser this qustion plesc ? Consider a Computer which has a memory which is capable of storing 4096 K words and each word in memory can be of size 32 bits. The computer supports a total of “K” addressing modes, and it has “M” computer registers. The computer supports instructions, where each instruction consists of following fields: Mode Operation code Register Register Memory AddressGiven that each instruction will be stored in one memory word, discuss with a suitable diagram the format of instruction by specifying number of bits for each field of instruction. Discuss each field of instruction.Note: Choose your own values for K (number of addressing modes) and M (number of Registers) k=8 m=50