n13Total Number of Atoms in a Body centered Cubic (BCC) Structure isedSelect one:out ofO 2questionO 4O 1on 14Which of the following is the unit for electrical conductivity?eteredSelect one:ed out ofO (Q-m) -1g questionO (2-mm)O m/SO Q-mP Type here to search99+hp**f4f5f6

BCC stands for Body centered cubic structure. It is the third common packing arrangement in metals.…

Answered: Total Number of Atoms in a Body…

Total Number of Atoms in a Body centered Cubic (BCC) Structure is Select one: O 2 O 6 O 4 O 1 Which of the following is the unit for electrical conductivity? Select one: O (2-m)-1 O(2-mm) O m/S O Q-m

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)

8th Edition

ISBN:9781305387102

Author:Kreith, Frank; Manglik, Raj M.

Publisher:Kreith, Frank; Manglik, Raj M.

Chapter1: Basic Modes Of Heat Transfer

Section: Chapter Questions

Problem 1.71P: 1.71 The thermal conductivity of silver at 212°F is 238 Btu/h ft °F. What is the conductivity in SI...

See similar textbooks

Related questions

Q: Molybdenum has an atomic radius of 0.145nm. The volume of its cubic unit cell is 0.0375 nm3 . What…

A: The data given is, The volume of the cubic unit cell, V = 0.0375 nm3 The atomic radius of the…

Q: The atomic packing factor for a material with body centred cubic structure is....

A: We can find the answer as below

Q: Q3: A unit cell of diamond structure belongs to the cubic crystal system and contains eight atoms of…

Q: (a ) Rhodium has an atomic radius of 0.1345 nm and a density of 12.41 g/cm^3 . Determine whether it…

A: **According to the guide-lines we are allowed to answer only one question at a time. Please…

Q: Question Four: a) Calculate the packing fraction for the diamond structure. b) Specify the lattice,…

Q: Scandium (Sc) has the Face-Centered Cubic (FCC) crystal structure. The edge length is a = 0.452 nm.…

Q: Consider an fcc lattice with cube side length 2.7 Ă. What are the planar densities of the (110) and…

Q: The crystal structure of beryllium is Oa. Orthorhombic O b. H.C.P O c. F.C.C. O d. B.C.C.

A: Correct option: b) H.C.P

Q: Silver crystallizes as fcc structure. If the density of silver is 10.51g/cm3. Calculate the volume…

Q: 6- The Atomic Packing factors Of (APF) Hexagonal Close packed (HCP) is * 6. O 0.74 0.68

A: HCP or hexagonal closed packing is a type of arrangement in crystal lattices.

Q: The total number of atom present in a simple cubic unit cell structure is O Eight O Four O Two O One

A: Total number of atom present in a simple cubic unit cell structure is two In simple cubic no. of…

Q: According to the hard-sphere model, illustrate with draw figure the contributions of atoms in the…

Q: The density of BCC iron is 7.882g/cm3 and the lattice parameter is 0.2866nm when hydrogen atoms are…

Q: 1) Explain the Fáčé-Céntéřéd Cübić unit cell with a neat diagram and provide a minimum of two…

A: An FCC unit cell contains particles at all the corners of the crystal cross section and at the…

Q: Nickel (Ni) has the Face-Centered Cubic (FCC) crystal structure. The edge length is a = 0.3536 nm.…

Q: Consider two hypothetical metallic crystal structures A and B. A has an fcc and Ba bcc lattice…

Q: In the' simple cubic crystal lattice'structure, specify the 'Atomic fill factor' and the 'Planar…

A: Simple cubic crystal eight atoms at the eight cornors of the cubeLattice parameter or side length of…

Q: 8- Tungsten W (atomic weight = 183.84 g/mol) forms a body centered cubic (bcc) unit cell. If…

Q: What are the Miller indices for the plane shown in the following unit cell?

Q: One form of TiO2 is the mineral rutile, which has a tetragonal lattice with a = b= 4.594 x 10-10 m…

Q: An FCC crystal structure is supposed to have this characteristic. Equal lattices (a = b = c) (101)…

A: Ghgh

Q: Calculate the volume of an FCC(Face Center Cubic) unit cell (cell edge length a) in terms of the…

A: It is required to determine volume of FCC Unit cell

Q: A material x has a crystal structure of FCC and lattice parameter 4.82 angstrom. Write down the…

Q: Total number of atoms present in a unit cell of body centered cubic structure is O One O Three O Two…

A: In BCC structure there is total of

Q: Scandium (Sc) has the FCC crystal structure. The atomic radius is R = 0.16 nm %3D and the atomic…

A: Given: Atomic radius of Nickel is, R=0.16 nm=1.6×10-8 cm Atomic weight of Nickel is, W=44.96 g/mol…

Q: 1 The coordination number for the HCP unit cell is (b) 12 (17 (a) 14 2 Select an image in which all…

A: As per our guidelines we are supposed to answer only one question. Kindly repost other question as a…

Q: NaCl crystals have FCC structure. The density of NaCl is 2.18 g/cc. Calculate the distance between…

A: given is density of NaCl (d) = 2.18 g/cc since the structure of NaCl is FCC thus Z = 4 where Z…

Q: The distance between the two (111) planes in the FCC crystal structure is 0.2 nm. Find out the…

A: Given data: The distance between two FCC planes is d=0.2nm The plane of the crystal structure is…

Q: Problem 4. Calculate a value for the density of FCC platinum in grams per cubic centimeter from its…

A: solved

Q: Q 7(a): Derive planar density expressions for FCC (100) and (111) planes in terms of the atomic…

Q: The twin boundaries of FCC and BCC structures are. and respectively. *

A: Annealing twins, most prevalent in Face Centered Cubic (FCC) metals e.g. aluminum, copper, brass…

Q: (c) The unit cell for Al;Os has hexagonal symmetry with lattice parameters a -0.4759 nm and c- 1.29…

A: Solution:

Q: z1 z1 y2 x3 1/4 G 3/4 1/2 y1 y1 3/2 x2 B 1/2 х1 z2 y3 x1 FIGURA 1 FIGURA 2

A: Miller indices of the given planes =Coordinates of plane 'A' = 1,12,34miller indices for a given…

Q: 2. A 2D representation of crystalline structure is shown below. Please indicate the type of defects…

A: a) Vacancy defect: This defect is due to missing of an atom from crystal lattice. Due to this defect…

Q: An atom crystallizes in FCC crystal lattice and has a density of 10 g/ cm 3 with unit cell edge…

A: Given, Density (ρ) = 10 g/cm3 Edge length (a) = 100pm = 100×10-10 cm = 10-8 cm…

Q: Calculate the linear density of an FCC along (1 1 0) and the theoretical density. 1. Aluminum…

Q: 6- The Atomic Packing factors Of (APF) Hexagonal Close packed (HCP) i * 6 O 12 O 0.74 O 0.68

A: To determine the atomic packing factor of HCP structure.

Q: Calculate the planar atomic density of (110) for diamond structure.

Q: Calculate the packing fraction of body centred cubic structure (b.c.c) and face centred cubic…

Q: What is the coordination number for atoms in the HCP structure? How does this compare to the…

A: (1) In the entire crystal, a unit cell is the smallest representation. All crystal lattices are made…

Q: Nickel has face -centered (FCC) cubic structure and atomic mass is 58.69. The atomic radius of…

Q: Copper crystallizes in FCC structure. Its density is 8960 kg/m3 and atomic weight is 63.54. Find…

Q: uestion Six: For an FCC crystal: calculate the density of atoms (atoms/a where a is the lattice…

A: here the radius of the atom is given a For the FCC crystal structure, the planar density for the…

Q: 1 GO 1) Calculate density of an atom of Polonium in g/cm 2) Calculate density of the atom of Nickel…

A: Given: The mass of polonium per mole, mpo = 202 g/mol The radius of polonium atom, rpo = 336x10-12 m…

Q: Consider two hypothetical metallic crystal structures A and B. A has a simple cubic and B a fcc…

A: Given: Atomic packing factor For A = 0.52 (simple cubic structure) For B = 0.74 (FCC structure)

Q: Platinum has a lattice constant of 0.39239 nm and its atomic mass is 195.09 g/mol. Calculate a value…

Q: The coordination number of netal atoms in FCC crystal is 12

A: Given: The coordination number of FCC structure is 12 To determine: The statement is true or false

Q: Europium has the Body-Centered Cubic (BCC) crystal structure shown in the figure below. The radius…

Q: Determine the indices for the directions in the cubic unit cell shown in below Figure 3 4 C D A B)

Q: "otassium (K) has the Body-Centered Cubic (BCC) crystal structure. The edge length is Vhat is the…

A: GivenBBC structure direction 011

Concept explainers

The Space Lattice and Unit Cells

Every matter consists of atoms, molecules, and ions. If these atoms, molecules, and ions (micro-particles) are represented in a three-dimensional space-occupying certain specific points in space, then these arrangements are termed as space lattices and the specific points which are being occupied by atoms, molecules and ions are termed as lattice points. The atoms, molecules, and ions at the lattice points are generally grouped in a regular fashion and repeat periodically at the three-dimensional space.

Question

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Step by step

Solved in 3 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Principal Metallic Crystal Structures and Crystal Structure Analysis

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions

What is the volume of 3.00 moles of copper? Molar mass of copper is 63.546 g/mol and its density is 8.9 x 103 kg/m3.
Some hypothetical alloy is composed of 25 wt% of metal A and 75 wt% of metal B. If the densities of metals A and b are 6.17 and 8.00 g/cm^3 respectively, whereas their respective atomic weights are 171.3 g/mol and 162 g/mol respectively, determine the crystalline structure of the alloy assuming a unit cell edge length of 0.332 nm.
The attached photo shows the Young’s modulus of a cubic single crystal as a function of orientation. where a1 a2 and a3 are the direction cosines between the direction hkl and [100], [010], and [001], respectively. For a certain crystal, E111 = 500 GPa and E100 = 90 GPa. Calculate Young’s modulus for this single crystal in the <110> direction
Calculate the number of vacancies per cubic meter at 1000°C for a metal that has an energy for vacancy formation of 1.22 eV/atom, a density of 6.25 g/cm3, and an atomic weight of 37.4 g/mol.</o:p> (A) 1.49 ×1018 m−3</o:p> (B) 7.18 ×1022 m−3</o:p> (C) 1.49 ×1024 m−3</o:p> (D) 2.57 ×1024 m−3</o:p>
1). A large chunk of metal has a mass of 544.3 kg, and its volume is measured to be 0.0480 m3. (i). Find the metal’s mass density and weight density in SI unit. ii). What kind of metal is this? (2). Will the mass density of metal be different on the moon than it is on Earth? What about the weight density? Explain your answer.
(a ) Rhodium has an atomic radius of 0.1345 nm and a density of 12.41 g/cm^3 . Determine whether it has an FCC or BCC crystal structure. (Note: It has an atomic weight of 102.91 g/mol.) (b) If aluminum diffused into a thick slice of silicon with no previous aluminum in it at the temperature of 1100 degrees celcius for 6 hours, what is the depth below the surface at which the concentration is 1016 atoms/cm^3 if the surface concentration is 1018 atoms/cm^3 . D=2x10^(-12) cm^2 /s for Al diffusing in Si at 1100 degrees celcius.
142) What property does a bonded material with an electron cloud not exhibit?a) Conductivityb) Heat conductionc) Toughnessd) Ductilitye) An opaque appearance 143) Which have equal and oppositely charged forces?A) DipoleB) metalC) van der waalsD) hydrogenE) london 144) What is Frenkel error?A) atomic vacuumB) displaced ionC) intermediate atomD) ion pair spacingE) slip
Determine in [kg / m3] the density of calcium (FCC) that has a radius atomic R = 0.1976 nm.
6. If we approximate the atmosphere to be 79% Nitrogen (N2) by volume and 21% oxygen (O2), estimate the density of air (kg/m3) and ppmv at 1 atmosphere and ambient temperatures of 40 C and 450 C. (Atomic weight of nitrogen=14)
What is the surface area of spheres with the diameter a and fcc structure packed into the same volume as the 1-nm cubes within 1 m^3? Face-centered cubic structures have a packing factor of 0.74. 4.44x10^27 nm^2 4.78x10^28 nm^2 5.89x10^26 nm^2 3.21x10^25 nm^2
1. Calculate the density of a high-leaded brass with a composition of 64.5 wt% Cu, 33.5 wt% Zn, and 2 wt% Pb. Cu, Zn, and Pb have densities of 8.96 m, 7.133 g cm-3, and 11.29 g cm-3, respectively, at ambient temperature.
Gallium has an orthorhombic structure,with a0 5 0.45258 nm, b0 5 0.45186 nm,and c0 5 0.76570 nm. The atomic radiusis 0.1218 nm. The density is 5.904 g/cm3,and the atomic weight is 69.72 g/mol.Determine(a) the number of atoms in each unit cell;and(b) the packing factor in the unit cell.