Trace the following execution:
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- This is in JAVA For what values of integer x will Branch 3 execute? If x < 10 : Branch 1<br/> Else If x > 9: Branch 2 Else: Branch 3 A. Value 10 or larger B. Value 10 only C. Values between 9 and 10 D. For no values (never executes)Find the problem with the logic of the below program, assuming all system calls are successful. The problem is not about compile or run-time errors int fd[2]; pipe(fd); for(int i = 0; i < 10; ++i){ int childpid = fork(); if (childpid == 0){ close(fd[0]); for(int j = 0; j < 10; ++j) write(fd[1], j, sizeof(int)); exit(0); } }fill in the blanks Write the missing instructions to complete the codes for Sleeping Barbers problem solution: Shared data: customer = 0, barber = 0, mutex = 1; int waiting = 0; CHAIR = 5; Barber Customers while (TRUE) {______ ( customer ); wait ( mutex ); waiting - -; signal ( barber ); signal ( mutex ); .... cut hair();} while ( TRUE ) { wait ( mutex ); if ( waiting < CHAIR) { waiting + +; signal ( customer ); ( mutex ); wait ( ); ….. get haircut(); } else signal ( mutex);}
- On a piano, a key has a frequency, say f0. Each higher key (black or white) has a frequency of f0 * rn, where n is the distance (number of keys) from that key, and r is 2(1/12). Given an initial key frequency, output that frequency and the next 4 higher key frequencies. Output each floating-point value with two digits after the decimal point, which can be achieved by executingcout << fixed << setprecision(2); once before all other cout statements.Implement the counter increment, and branch back to the start of the loop. When you havecompleted these steps, the basic structure of the counter control loop has been implemented,and your code should look similar to the following:.text li $s0, 0 lw $s1, n start_loop: sle $t1, $s0, $s1 beqz $t1, end_loop # code block addi $s0, $s0, 1 b start_loop end_loop:.data n: .word 5write in assembly language usinf LC3 simulator LC3 simulator to use: https://wchargin.com/lc3web/ Implement an if-else statementa. An if-else statement will execute one out of two blocks of codeb. Your if-else statement should check if R0 = R1, then make R3 = 5, if R0 ≠ R1, then make R3 = -5c. You can manually modify R0, R1, and R3, in the simulator (before running your program only). You do nothave to program values for these registers Psuedo code: .ORIG x3000 ; Two's Complement R1 (two instructions: negate and add 1) ; Initialize R3 with #0 ; Add R0 and R1; place result into R2 (are they equal? If they are, what value is in R2?) ; Branch if non-zero to ELSE (they are not equal in this case) IF ; Place #5 in R3 ; Branch to done ELSE ; Place #-5 in R3 DONE ; Halt CPU .END
- Suppose we execute the following code. int main() { fork(); printf("hello"); fork(); printf("hello"); } Suppose then, all calls to fork() were successful. How many instances of "hello" would you expect to see printed to standard output? Enter your answer as an integer.THIS IS IN JAVA Which value of x results in short circuit evaluation, causing y < 4 to not be evaluated? <pre><code>(x >= 7) && (y < 4)</code></pre> A. 6 B. 7 C. 8 D. No Such ValueWhat seems the problem here? Im using Programiz's Javascript compilerCODE://Print menuconsole.log("1: String Concatenation")console.log("2: String Comparison")console.log("3: Fibonacci Sequence")console.log("4: Floyd Triangle")console.log("5: Quit")//User input var n = prompt("Choose one: ");//Compare choice and perform required operationswitch (n) { case 1: var string1 = prompt("Enter the first string: "); var string2 = prompt("Enter the second string: "); alert(string1 + string2); break; case 2: var string1 = prompt("Enter the first string: "); var string2 = prompt("Enter the second string: "); if (string1 == string2) { alert("The strings are equal"); } else { alert("The strings are not equal"); } break; case 3: var n = prompt("Enter the number of terms: "); var a = 0; var b = 1; var c; alert("The Fibonacci sequence is: "); alert(a); alert(b); for (i = 2; i < n; i++) { c = a + b; a = b; b = c;…
- On a piano, a key has a frequency, say f0. Each higher key (black or white) has a frequency of f0 * rn, where n is the distance (number of keys) from that key, and r is 2(1/12). Given an initial key frequency, output that frequency and the next 4 higher key frequencies. Output each floating-point value with two digits after the decimal point, which can be achieved by executingcout << fixed << setprecision(2); once before all other cout statements. Ex: If the input is: 440.0 (which is the A key near the middle of a piano keyboard), the output is: 440.00 466.16 493.88 523.25 554.37 Note: Use one statement to compute r = 2(1/12) using the pow function (remember to include the cmath library). Then use that r in subsequent statements that use the formula fn = f0 * rn with n being 1, 2, 3, and finally 4.On a piano, a key has a frequency, say f0. Each higher key (black or white) has a frequency of f0 * rn, where n is the distance (number of keys) from that key, and r is 2(1/12). Given an initial key frequency, output that frequency and the next 4 higher key frequencies. Output each floating-point value with two digits after the decimal point, which can be achieved by executingcout << fixed << setprecision(2); once before all other cout statements. Ex: If the input is: 440.0 (which is the A key near the middle of a piano keyboard), the output is: 440.00 466.16 493.88 523.25 554.37 Note: Use one statement to compute r = 2(1/12) using the pow function (remember to include the cmath library). Then use that r in subsequent statements that use the formula fn = f0 * rn with n being 1, 2, 3, and finally 4. I am having trouble putting them on one sentence line.Write a program in sim8085 with attacked output for the problem: PROBLEM STATEMENT- In a food processing industry, different food products are packed and identified with numbers and ready to be transported. The Following food packages are kept in the conveyer belt, and it is sent through a detector unit. Write a program sequence to detect number of D3 items passed through the detector unit and store the count in ‘D’ Register. Data: 12, F3, 56, D3, 01, 47, D3, 21, D3, 00, 67, D3, D3, 14.