Tracey wrote the definition of a function, remove_last (phrase), which takes in a string phrase, consisting of words separated by spaces. The function is supposed to return the phrase with the words in the same order, but with the last letter of each word removed. For example, remove_last('one two three four five six') should return 'on tw thre fou fiv si' Unfortunately, her archrival, the Code Mangler, has jumbled the last six lines into the incorrect order, removed all the indentation, and added bogus lines it created using machine learning. Your job is to take the below lines of code, labeled A-J, and rearrange them to finish the working function. You will only use 6 of the 10 lines. #First line of the function #You must add 6 more lines def remove_last (phrase): word = words[i] #A words = phrase.split() #B for word in phrase: #C for i in range (len (words)): #D words.append(word) #E word [1:] #F word = return phrase #G words[i] = word #H

Tracey wrote the definition of a function, remove_last (phrase), which takes in a string phrase, consisting of words separated by spaces. The function is supposed to return the phrase with the words in the same order, but with the last letter of each word removed. For example, remove_last('one two three four five six') should return 'on tw thre fou fiv si' Unfortunately, her archrival, the Code Mangler, has jumbled the last six lines into the incorrect order, removed all the indentation, and added bogus lines it created using machine learning. Your job is to take the below lines of code, labeled A-J, and rearrange them to finish the working function. You will only use 6 of the 10 lines. #First line of the function #You must add 6 more lines def remove_last (phrase): word = words[i] #A words = phrase.split() #B for word in phrase: #C for i in range (len (words)): #D words.append(word) #E word [1:] #F word = return phrase #G words[i] = word #H

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Can you please implement the function in this .c file down below, the function to implement have "To do :" on them? #include <stdlib.h>#include <stdio.h>#include <string.h>#include <monetary.h> #include "team.h" const int NUM_TEAMS = 16; void initTeam(Team *t, char *name, int wins, int loss, char *city, char *state, double payroll, double aveSalary) { t->name = (char *)malloc(sizeof(char) * (strlen(name) + 1)); strcpy(t->name, name); t->wins = wins; t->loss = loss; t->city = (char *)malloc(sizeof(char) * (strlen(city) + 1)); strcpy(t->city, city); t->state = (char *)malloc(sizeof(char) * (strlen(state) + 1)); strcpy(t->state, state); t->payroll = payroll; t->averageSalary = aveSalary; } void printTeam(const Team *t) { if (t == NULL) { printf("null\n"); return; } double winPerc = 100.0 * t->wins / (double)(t->wins + t->loss); printf("%-10s %3d %3d (%5.2f) %-15s %2s $%12.2f $%9.2f\n",…
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Write a function called remove_punct() that accepts an array of characters and the number of items in the array as parameters, removes the punctuation (',', '!', '.') characters from the array, and returns the number of punctuation characters removed. For example, if the array contains ['C', 'p', 't', 'S', ',', '1', '2', '1', '.', 'i', 's', 'f', 'u', 'n', '!'], then the function should remove the punctuation characters. The function must remove the characters by shifting all characters to the right of each punctuation character, left by one spot in the array. This will overwrite the punctuation characters, resulting in: ['C', 'p', 't', 'S', '1', '2', '1', 'i', 's', 'f', 'u', 'n']. In this case, the function returns 3. Note: if the array does not contain any punctuation characters, then the array is unchanged and the function returns 0.
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